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Sveta_85 [38]
8 months ago
12

If a maserati. with a belocity of 6 m/s E, accelerates at a rate of 85 m/s^2 for 5 seconds, what will its velocity be?

Physics
1 answer:
Ksju [112]8 months ago
7 0

The final velocity of the Maserati after accelerating at the rate of 85 m/s² for 5 seconds is 431m/s.

<h3>How to calculate the final velocity a moving object?</h3>

From the first equation of equation of motion, final velocity is the sum of the initial velocity and the product of acceleration and time.

It is expressed as;

v = u + at

Where v is final velocity, u is initial velocity, a is acceleration and t is time elapsed.

Given the data in the question;

  • Initial velocity u = 6m/s
  • Acceleration a = 85m/s²
  • Elapsed time t = 5s
  • Final velocity v = ?

Plug the given values into the first equation of motion and solve for v.

v = u + at

v = 6m/s + ( 85m/s² × 5s )

v = 6m/s + 425ms/s²

v = 6m/s + 425m/s

v = 431m/s

The final velocity of the Maserati after accelerating at the rate of 85 m/s² for 5 seconds is 431m/s.

Learn more about the first equation of equation here: brainly.com/question/20381052

#SPJ1

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A body is projected from the ground at an angle of 30° with the horizontal at an initial speed of 128 ft/s. Ignoring air frictio
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Answer

given,

v = 128 ft/s

angle made with horizontal = 30°

now,

horizontal component of velocity

vx = v cos θ = 128 x cos 30° = 110.85 ft/s

vertical component of velocity

vy = v sin θ = 128 x sin 30° = 64 m/s

time taken to strike the ground

using equation of motion

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0 =-64 -32 x t

t = 2 s

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b) maximum height

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  h = 64 ft

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