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7 months ago

If a maserati. with a belocity of 6 m/s E, accelerates at a rate of 85 m/s^2 for 5 seconds, what will its velocity be?

Physics

1 answer:

Ksju [112]7 months ago

7 0

The final velocity of the Maserati after accelerating at the rate of 85 m/s² for 5 seconds is 431m/s.

<h3>How to calculate the final velocity a moving object?</h3>

From the first equation of equation of motion, final velocity is the sum of the initial velocity and the product of acceleration and time.

It is expressed as;

v = u + at

Where v is final velocity, u is initial velocity, a is acceleration and t is time elapsed.

Given the data in the question;

Initial velocity u = 6m/s
Acceleration a = 85m/s²
Elapsed time t = 5s
Final velocity v = ?

Plug the given values into the first equation of motion and solve for v.

v = u + at

v = 6m/s + ( 85m/s² × 5s )

v = 6m/s + 425ms/s²

v = 6m/s + 425m/s

v = 431m/s

The final velocity of the Maserati after accelerating at the rate of 85 m/s² for 5 seconds is 431m/s.

Learn more about the first equation of equation here: brainly.com/question/20381052

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A 2.31 kg rope is stretched between supports 10.4 m apart. If one end of the rope is tweaked, how long will it take for the resu

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Answer:

t = 0.657 s

Explanation:

First, let's use the appropiate equations to solve this:

V = √T/u

This expression gives us a relation between speed of a disturbance and the properties of the material, in this case, the rope.

Where:

V: Speed of the disturbance

T: Tension of the rope

u: linear density of the rope.

The density of the rope can be calculated using the following expression:

u = M/L

Where:

M: mass of the rope

L: Length of the rope.

We already have the mass and length, which is the distance of the rope with the supports. Replacing the data we have:

u = 2.31 / 10.4 = 0.222 kg/m

Now, replacing in the first equation:

V = √55.7/0.222 = √250.9

V = 15.84 m/s

Finally the time can be calculated with the following expression:

V = L/t ----> t = L/V

Replacing:

t = 10.4 / 15.84

t = 0.657 s

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Answer:

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The intensity of light from a star (its brightness) is the power it outputs divided by the surface area over which it’s spread:

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Answer:

$\frac{d_{1}}{d_{2}}=0.36$

Explanation:

1. We can find the temperature of each star using the Wien's Law. This law is given by:

$\lambda_{max}=\frac{b}{T}=\frac{2.9x10^{-3}[mK]}{T[K]}$ (1)

So, the temperature of the first and the second star will be:

$T_{1}=3866.7 K$

$T_{2}=6444.4 K$

Now the relation between the absolute luminosity and apparent brightness is given:

$L=l\cdot 4\pi r^{2}$ (2)

Where:

L is the absolute luminosity
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r is the distance from us in light years

Now, we know that two stars have the same apparent brightness, in other words l₁ = l₂

If we use the equation (2) we have:

$\frac{L_{1}}{4\pi r_{1}^2}=\frac{L_{2}}{4\pi r_{2}^2}$

So the relative distance between both stars will be:

$\left(\frac{d_{1}}{d_{2}}\right)^{2}=\frac{L_{1}}{L_{2}}$ (3)

The Boltzmann Law says, $L=A\sigma T^{4}$ (4)

σ is the Boltzmann constant
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Let's put (4) in (3) for each star.

$\left(\frac{d_{1}}{d_{2}}\right)^{2}=\frac{A_{1}\sigma T_{1}^{4}}{A_{2}\sigma T_{2}^{4}}$

As we know both stars have the same size we can canceled out the areas.

$\left(\frac{d_{1}}{d_{2}}\right)^{2}=\frac{T_{1}^{4}}{T_{2}^{4}}$

$\frac{d_{1}}{d_{2}}=\sqrt{\frac{T_{1}^{4}}{T_{2}^{4}}}$

$\frac{d_{1}}{d_{2}}=0.36$

I hope it helps!

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