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Sveta_85 [38]
1 year ago
12

If a maserati. with a belocity of 6 m/s E, accelerates at a rate of 85 m/s^2 for 5 seconds, what will its velocity be?

Physics
1 answer:
Ksju [112]1 year ago
7 0

The final velocity of the Maserati after accelerating at the rate of 85 m/s² for 5 seconds is 431m/s.

<h3>How to calculate the final velocity a moving object?</h3>

From the first equation of equation of motion, final velocity is the sum of the initial velocity and the product of acceleration and time.

It is expressed as;

v = u + at

Where v is final velocity, u is initial velocity, a is acceleration and t is time elapsed.

Given the data in the question;

  • Initial velocity u = 6m/s
  • Acceleration a = 85m/s²
  • Elapsed time t = 5s
  • Final velocity v = ?

Plug the given values into the first equation of motion and solve for v.

v = u + at

v = 6m/s + ( 85m/s² × 5s )

v = 6m/s + 425ms/s²

v = 6m/s + 425m/s

v = 431m/s

The final velocity of the Maserati after accelerating at the rate of 85 m/s² for 5 seconds is 431m/s.

Learn more about the first equation of equation here: brainly.com/question/20381052

#SPJ1

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malfutka [58]

In order to determine the acceleration of the block, use the following formula:

F=ma

Moreover, remind that for an object attached to a spring the magnitude of the force acting over a mass is given by:

F=kx

Then, you have:

ma=kx

by solving for a, you obtain:

a=\frac{kx}{m}

In this case, you have:

k: spring constant = 100N/m

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x: distance related to the equilibrium position = 14cm - 12cm = 2cm = 0.02m

Replace the previous values of the parameters into the expression for a:

a=\frac{(\frac{100N}{m})(0.02m)}{0.2\operatorname{kg}}=10\frac{m}{s^2}

Hence, the acceleration of the block is 10 m/s^2

8 0
1 year ago
An electron is confined in a harmonic oscillator potential well. What is the longest wavelength of light that the electron can a
kipiarov [429]

Answer:

The longest wavelength of light is 209 nm.

Explanation:

Given that,

Spring constant = 74 N/m

Mass of electron m= 9.11\times10^{-31}\ kg

Speed of light c= 3\times10^{8}\ m/s

We need to calculate the frequency

Using formula of frequency

f =\dfrac{1}{2\pi}\sqrt{\dfrac{k}{m}}

Where, k= spring constant

m = mass of the particle

Put the value into the formula

f=\dfrac{1}{2\pi}\sqrt{\dfrac{74}{9.11\times10^{-31}}}

f=1.434\times10^{15}\ Hz

We need to calculate the longest wavelength that the electron  can absorb

\lambda=\dfrac{c}{f}

Where, c = speed of light

f = frequency

Put the value into the formula

\lambda =\dfrac{3\times10^{8}}{1.434\times10^{15}}

\lambda=2.092\times10^{-7}\ m

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6 0
3 years ago
What kind of frequency do radio waves have?<br><br>A. High frequency <br><br>B. Low frequency ​
inn [45]
B low frequency it is the lowest frequency
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A disk-shaped platform has a known rotational inertia ID. The platform is mounted on a fixed axle and rotates in a horizontal pl
Zarrin [17]

Answer:

Explanation:

The angular momentum of that same disk-sphere remains unchanged the very same way before and after the impact of the collision when the clay sphere adheres to the disk.

 \mathbf{I_w} = constant.

The overall value of such moment of inertia is now altered when the clay spherical sticks. Due to the inclusion of the clay sphere, the moment of inertia will essentially rise. As a result of this increase, the angular speed w decreases in value.

Recall that:

The Kinetic energy is given by:

\mathbf{K = \dfrac{1}{2} Iw^2} \\ \\\mathbf{K = \dfrac{1}{2} lw*w}

where;

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As a result, just after the collision, the system's total kinetic energy decreases.

5 0
3 years ago
A wire has a current density of 6.25 × 10 6 A / m 2 6.25×106 A/m2 . If the cross-sectional area of the wire is 1.79 mm 2 1.79 mm
joja [24]

Answer:17.44A

Explanation: Current density=I/Area

Area is given by 2.79mm^2=2.79×10^-6m^2

Current=I=current density ×Area=6.25×10^6 ×2.79×10^-6=17.44A

3 0
3 years ago
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