An Object with a mass of 40kg is moving at a velocity of 10 m/s. Determine its kinetic energy

Physics

1 answer:

olga55 [171]2 years ago

5 0

Answer:

KE = 2000 J

Explanation:

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How long will a plane have to fly continuously with 900 miles per hour in order to cover the same distance as that from Earth to

hammer [34]

I'm not sure about the distance to the nearest star, but it's probably about 4 light-years (L-y).

1 L-y = 1.86 * 10E5 mi/sec * 3600 sec/hr * 24 hr/day * 365 day/yr

1 L-y = 5.9 *10E12 mi and 4 L-y = 2.3 *10E13 mi distance to star

2.3 * 10E13 mi / 900 mi/hr = 2.6 * 10E10 hr hours to star

2.6 * 10E10 hr / (24 hr/day) = 1.1 * 10E9 day days to star

1.1 * 10E9 day / 365 day/yr = 3 * 10E6 yr = 3 million years to star

4 0

2 years ago

A ray of light incident in air strikes a rectangular glass block of refractive index 1.50, at an angle of incidence of 45°. Calc

balandron [24]

Answer:

Approximately $28^{\circ}$ .

Explanation:

The refractive index of the air $n_{\text{air}}$ is approximately $1.00$ .

Let $n_\text{glass}$ denote the refractive index of the glass block, and let $\theta _{\text{glass}}$ denote the angle of refraction in the glass. Let $\theta_\text{air}$ denote the angle at which the light enters the glass block from the air.

By Snell's Law:

$n_{\text{glass}} \, \sin(\theta_{\text{glass}}) = n_{\text{air}} \, \sin(\theta_{\text{air}})$ .

Rearrange the Snell's Law equation to obtain:

$\begin{aligned} \sin(\theta_{\text{glass}}) &= \frac{n_{\text{air}} \, \sin(\theta_{\text{air}})}{n_{\text{glass}}} \\ &= \frac{(1.00)\, (\sin(45^{\circ}))}{1.50} \\ &\approx 0.471\end{aligned}$ .