Calculate the force of an object that has a mass of 10kg and an acceleration of 4m/s²

How far will a rubber ball fall in 10 seconds?

Inessa [10]

If it's not moving at all at the beginning of the 10 seconds, then it falls 490 meters straight down in 10 seconds.

(Note: This is true of all objects on Earth . . . rubber balls, feathers, grains of sand, school buses, battle ships . . . everything. As long as air doesn't hold them back. Anything falling from rest falls 490 meters in the first 10 seconds.)

4 0

3 years ago

If the area of a concrete slap weighing 300n is 400cm2 ,how much pressure can it apply when kept on the ground

aleksklad [387]

Answer:

7500 N/m²

Explanation:

From the question given above, the following data were obtained:

Force (F) = 300 N

Area (A) = 400 cm²

Pressure (P) =?

Next, we shall convert 400 cm² to m². This can be obtained as follow:

1×10⁴ cm² = 1 m²

Therefore,

400 cm² = 400 cm² × 1 m² / 1×10⁴ cm²

400 cm² = 0.04 m²

Finally, we shall determine the pressure. This can be obtained as follow:

Force (F) = 300 N

Area (A) = 0.04 m²

Pressure (P) =?

P = F/A

P = 300 / 0.04

P = 7500 N/m²

3 0

3 years ago

Which of the following describes an electric conductor?

Sliva [168]

A substance which allows the un-interrupted flow of electric current is called an electric conductor

7 0

3 years ago

Read 2 more answers

A 0.50 mm-wide slit is illuminated by light of wavelength 500 nm.What is the width of the central maximum on a screen 2.0m behin

Novay_Z [31]

Answer:

0.004 m

Explanation:

For light passing through a single slit, the position of the nth-minimum in the diffraction pattern is given by

$y=\frac{n\lambda D}{d}$

where

$\lambda$ is the wavelength

D is the distance of the screen from the slit

d is the width of the slit

Therefore, the width of the central maximum is equal to twice the value of y for n=1 (first minimum):

$w=2\frac{\lambda D}{d}$

where we have

$\lambda=500 nm = 5\cdot 10^{-7}m$ is the wavelength

D = 2.0 m is the distance of the screen

$d=0.50 mm=5\cdot 10^{-4}m$ is the width of the slit

Substituting, we find

$w=2\frac{(5\cdot 10^{-7} m)(2.0 m)}{5\cdot 10^{-4} m}=0.004 m$

5 0

3 years ago

A wheel of mass M and radius R rolls on a level surface without slipping. If the angular velocity of the wheel about its center

Verizon [17]

The most important thing you should remember in order to get how is its linear momentum relative to the surface is that the<span> point on the circumference is moving at w rad/second.
Therefore, here is the solving formulae:
if </span> $v = R * w$ you can easily get <span> linear momentum p :
</span> $p = M * v = M * R * w$
I'm sure that helps.

4 0

3 years ago