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Sergeeva-Olga [200]
3 years ago
5

Demonstrate In A Brief Paragraph How The Search To Explain Planetary Orbits Exemplifies The Scientific Method

Chemistry
1 answer:
Sveta_85 [38]3 years ago
8 0

People firstly believe that the planets move in a circular orbit until Newton came up with his hypothesis by inventing calculus so that we could understood and calculated planetary orbits and their accuracy.

<u>Explanation:</u>

  • Everyone assumed the planets were perfect circles until Newton came up with an idea. Slowly people would make maps of the orbits that added circles on circles, and they could never really explain about the movement of the planet. They simply say that planets move on circles but they lacked the math to explain or prove it. Then Newton came up with an idea of inventing calculus so that we could understood and calculated planetary orbits and their accuracy.
  • Firstly people used their observations and say that the orbits looked like circles, then they developed their models and did the math, and proposed their hypothesizes which were wrong, until Newton came along and tried to match a model that used elliptical orbits and invented the math that allowed him to make predictions with it. His model worked for most planets.
  • However he could not explain about the planet Mercury for instance since it was a very strange orbit. Then after the Einstein's theory of General Relativity he could also explain very deeply about it.
  • Scientists and Astronomers made hypothesizes that there was another planet orbiting too close to the sun to see with telescopes, called Vulcan, that explained mercury's orbit before Einstein's theory. Then long after we had telescopes which was good enough to see if there was a planet orbiting closer to the sun than mercury.  
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lisov135 [29]

Answer:

DNA, or deoxyribonucleic acid, is the hereditary material in humans and almost all other organisms. Nearly every cell in a person's body has the same DNA.

EXPLANATION: SO THE CORRECT ANSWER IS

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7 0
3 years ago
What is the energy of a photon of red light that has a frequency of 4.48 X 10^14Hz?
lana [24]

Answer:

E = 29.7× 10⁻²⁰  j

Explanation:

Given data;

Frequency of light = 4.48 × 10¹⁴ Hz

Energy of photon = ?

Solution:

Formula:

E = h.f

E = energy of photon

h = planck's constant

f = frequency

E = h.f

E = 6.63 × 10⁻³⁴ Kg.m² /s × 4.48 × 10¹⁴ s⁻¹

E = 29.7× 10⁻²⁰ Kg.m²/s²

Kg.m²/s² = j

E = 29.7× 10⁻²⁰  j

3 0
3 years ago
Silicon has 2 isotopes, Silicon-28 with an abundance of 90% and Silicon-30 with an abundance of 10%. Find the AAM for Silicon.
JulsSmile [24]

Answer:

RAM

RAM = (mass \: of \:  ^{28} Si \:  \times \%abundance) + (mass \: of \:  ^{30} Si \:  \times \%abundance) \\ RAM = (28 \times 90\%) + (30 \times 10\%) \\ RAM = 25.2 + 3 \\ RAM = 28.2

5 0
2 years ago
Convert the volume to its equivalent in milliliters. 14 μL= ? mL
Diano4ka-milaya [45]
0.014 is the answer
6 0
3 years ago
Read 2 more answers
Calculate the equilibrium constant k for the isomerization of glucose-1-phosphate to fructose-6-phosphate at 298 k. express your
k0ka [10]
We cannot solve this problem without using empirical data. These reactions have already been experimented by scientists. The standard Gibb's free energy, ΔG°, (occurring in standard temperature of 298 Kelvin) are already reported in various literature. These are the known ΔG° for the appropriate reactions.

<span>glucose-1-phosphate⟶glucose-6-phosphate          ΔG∘=−7.28 kJ/mol
fructose-6-phosphate⟶glucose-6-phosphate          ΔG∘=−1.67 kJ/mol
</span>
Therefore, the reaction is a two-step process wherein glucose-6-phosphate is the intermediate product.

glucose-1-phosphate⟶glucose-6-phosphate⟶fructose-6-phosphate 

In this case, you simply add the ΔG°. However, since we need the reverse of the second reaction to end up with the terminal product, fructose-6-phosphate, you'll have to take the opposite sign of ΔG°.

ΔG°,total = −7.28 kJ/mol  + 1.67 kJ/mol = -5.61 kJ/mol

Then, the equation to relate ΔG° to the equilibrium constant K is

ΔG° = -RTlnK, where R is the gas constant equal to 0.008317 kJ/mol-K.
-5.61 kJ./mol = -(0.008317 kJ/mol-K)(298 K)(lnK)
lnK = 2.2635
K = e^2.2635
K = 9.62


6 0
3 years ago
Read 2 more answers
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