A sample of an unknown solid is found to have a volume of 24.3 cm3 and a mass of
1 answer:
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Answer:
Quantum numbers of the outermost electron in potassium:
.
.
.
- Either
.
Explanation:
Refer to the electron configuration of a potassium atom. The outermost electron in a ground-state potassium atom is in the orbital (fourth
orbital.)
The quantum number (the principal quantum number) specifies the main energy shell of an electron. This electron is in the fourth main energy shell (as seen in the number four in the orbital.) Hence,
for this electron.
The quantum number (the angular momentum quantum number) specifies the shape (
,
,
, etc.) of an electron.
for
orbitals (such as the one that contains this electron.
Quantum numbers and
specify the shape of an orbital. On the other hand, the magnetic quantum number
specifies the orientation of these orbitals in space.
However, orbitals are spherical. Regardless of the value of
, the only possible
value for electrons in
orbitals is
.
The spin quantum number distinguishes between the two electrons in an orbital. The two possible values of
are
and
. Typically, the first electron in an orbital is assigned an upward (
) spin, which corresponds to
.
Answer : 121.5 <span>μCi
Explanation : We have Ce-141 half life given as 32.5 days so if the activity is 3.8 </span><span>μci after 162.5 days of time elapsed we have to find the initial activity.
We can use this formula;
</span>
3.8 /
= 
((0.693 X 162.5 ) / 32.5) = 121.5
<span>
On solving we get, The initial activity as 121.5 </span>μci
Explanation : We have Ce-141 half life given as 32.5 days so if the activity is 3.8 </span><span>μci after 162.5 days of time elapsed we have to find the initial activity.
We can use this formula;
</span>
3.8 /
<span>
On solving we get, The initial activity as 121.5 </span>μci