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0.4 is the tenth in there.
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Answer:
Equation of tangent plane to given parametric equation is:

Step-by-step explanation:
Given equation
---(1)
Normal vector tangent to plane is:


Normal vector tangent to plane is given by:
![r_{u} \times r_{v} =det\left[\begin{array}{ccc}\hat{i}&\hat{j}&\hat{k}\\cos(v)&sin(v)&0\\-usin(v)&ucos(v)&1\end{array}\right]](https://tex.z-dn.net/?f=r_%7Bu%7D%20%5Ctimes%20r_%7Bv%7D%20%3Ddet%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%5Chat%7Bi%7D%26%5Chat%7Bj%7D%26%5Chat%7Bk%7D%5C%5Ccos%28v%29%26sin%28v%29%260%5C%5C-usin%28v%29%26ucos%28v%29%261%5Cend%7Barray%7D%5Cright%5D)
Expanding with first row

at u=5, v =π/3
---(2)
at u=5, v =π/3 (1) becomes,



From above eq coordinates of r₀ can be found as:

From (2) coordinates of normal vector can be found as
Equation of tangent line can be found as:

Answer: 180 = 30 + (x + 60)
Step-by-step explanation: Supplementary means that the angles add together to 180 degrees. This equations shows that angle A (30 degrees) plus angle B (x + 60) equal 180. If you solve the equation you will find that angle B is equal to 150 degrees, and that x = 90.
Look at the picture.
Domain: -4 ≤ x ≤ 4
Range: -1 ≤ y ≤ 1
<h3>Answer: {x | -4 ≤ x ≤ 4}</h3>