Angles a and b are supplementary how would you fix value of x
1 answer:
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Answer:
Domain → (-∞, -1)∪(-1, ∞)
Range → (-∞, ∞)
Step-by-step explanation:
Given function is,
This function is not defined when the denominator is zero.
2x + 2 = 0
2x = -2
x = -1
Therefore, x = -1 is not in the domain of this function.
And the domain will be,
(-∞, -1)∪(-1, ∞)
For all values of x (except x = -1) we get some output values (value of ).
Therefore, range of the function will be (-∞, ∞).