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Alexxx [7]
3 years ago
9

If grades are weighted 60% tests, 20% quizzes and 20% final exam... What is your course grade if you have a 75 test average, a 8

0 quiz average and make a 60 on the final
Mathematics
1 answer:
cricket20 [7]3 years ago
6 0

Answer:

73

Step-by-step explanation:

course grade = (75 x 0.6) + (80 x 0.2) + (60 x 0.2)  

                       =  45 + 16 + 12

                        = 73

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Please help I Don't understand
fredd [130]

Answer:

60 degrees

Step-by-step explanation:

I got the answer right

6 0
2 years ago
Read 2 more answers
Find the sum of the geometric series if n = 5, r = 2, a = 3.
posledela

Answer:

hope it helps you see the attachment for further information

sorry but my phone couldn't captured r=2

6 0
3 years ago
the arithmetic sequence ai is defined by the formula: a1 = -53 ai = ai-1 + 6 find the sum of the first 880 terms in the sequence
maxonik [38]

Answer:

The sum of the first 880 terms in the sequence is 2,273,920.

Step-by-step explanation:

Arithmetic sequence:

The difference between consecutive terms is always the same, called common difference, and the nth term is given by:

a_{n} = a_0 + (n-1)d

In which d is the common difference.

Sum of the first n terms:

The sum of the first n terms of an arithmetic sequence is given by:

S_{n} = \frac{n(a_1+a_n)}{2}

ai = ai-1 + 6

This means that d = 6

In this question:

Sum of the first 800 terms, so n = 800

First term is -53, so a_1 = -53

The 880th term is:

a_{880} = -53 + (880-1)*6 = 5221

Sum

S_{n} = \frac{880(-53+5221)}{2} = 440(-53+5221) = 2273920

The sum of the first 880 terms in the sequence is 2,273,920.

4 0
3 years ago
Can someone explain? It looks like none of these answers are right.
tresset_1 [31]
Answer: I think it’s E and D

Explanation:

Because they lie above the plane W not on the plane.
4 0
3 years ago
Make f the subject of the formula c=<img src="https://tex.z-dn.net/?f=%5Cfrac%7B5%28f-32%29%7D%7B9%7D" id="TexFormula1" title="\
lara31 [8.8K]

Answer:

f=\frac{9c}{5}+32

Step-by-step explanation:

c=\frac{5\left(f-32\right)}{9}

Switch sides:

\frac{5\left(f-32\right)}{9}=c

Multiply both sides by 9:

\frac{9\times5\left(f-32\right)}{9}=9c

5\left(f-32\right)=9c

Divide both sides by 5:

\frac{5\left(f-32\right)}{5}=\frac{9c}{5}

f-32=\frac{9c}{5}

Add 32 to both sides:

f-32+32=\frac{9c}{5}+32

f=\frac{9c}{5}+32

8 0
4 years ago
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