Four frequently used targeting strategies are the micromarketing, undifferentiated, differentiated, and E. concentrated targeting strategies. A targeting strategy allows a business to decide where segments of the market are most fitting for their product. The concentrated marketing strategy for targeting audience is when you focus on one specific market segment. Instead of having your product appeal to many audiences, it is set for just one specific audience.
Answer:
you can get more of one good only by giving up some of another good
Explanation:
A production possibilities frontier shows the opportunity cost of producing one good instead of another. This way, as you follow the curve, the combination of goods will vary, increasing the production of one good but deceasing the production of the other.
Opportunity costs are the benefits lost or extra costs associated to choosing one activity or investment over another alternative. Since resources are scarce, you must always give something up in order to obtain another thing, e.g. you give up your leisure time in order to study.
Answer:
d. a matter of establishing relationships.
Explanation:
Selling involves creating a relationship with the prospect.
The sales relationship has the short-term value you get from the customer.
There is also the long-term life-time value of the customer to be considered.
Sales based on referrals are the easiest to obtain and give best value.
Good relationships give rise to refrrals.
Answer:
a) $3
b) $2
c) 1449
Explanation:
Given:
The cost for a carton of milk = $3
Selling price for a carton of milk = $5
Salvage value = $0 [since When the milk expires, it is thrown out ]3
Mean of historical monthly demand = 1,500
Standard deviation = 200
Now,
a) cost of overstocking = Cost for a carton of milk - Salvage value
= $3 - $0
= $3
cost of under-stocking = Selling price - cost for a carton of milk
= $5 - $3
= $2
b) critical ratio = 
or
critical ratio = 
or
critical ratio = 0.4
c) optimal quantity of milk cartons = Mean + ( z × standard deviation )
here, z is the z-score for the critical ration of 0.4
we know
z-score(0.4) = -0.253
thus,
optimal quantity of milk cartons = 1,500 + ( -0.253 × 200 )
= 1500 - 50.6
= 1449.4 ≈ 1449 units
