Question

A ball is spun around in circular motion such that its frequency is 10 Hz.

Answer 1

Answer:

a = 0.1 s b. 10 s

Explanation:

Given that,

The frequency in circular motion, f = 10 Hz

(a) Let T is the period of itsrotation. We know that,

T = 1/f

So,

T = 1/10

= 0.1 s

(b) Frequency is number of rotations per unit time. So,

$t=\dfrac{n}{f}\\\\t=\dfrac{100}{10}\\\\t=10\ s$

Hence, this is the required solution.