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guajiro [1.7K]
3 years ago
9

In the simulation, both elastic and inelastic collisions take the same amount of time. In which type of collision is the acceler

ation less? Why?
Physics
1 answer:
Verdich [7]3 years ago
5 0

Answer:

its ealstic.

Explanation:

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An airplane flies eastward and always accelerates at a constant rate. At one position along its path it has a velocity of 34.3 m
Tomtit [17]

Explanation:

We'll need two equations.

v² = v₀² + 2a(x - x₀)

where v is the final velocity, v₀ is the initial velocity, a is the acceleration, x is the final position, and x₀ is the initial position.

x = x₀ + ½ (v + v₀)t

where t is time.

Given:

v = 47.5 m/s

v₀ = 34.3 m/s

x - x₀ = 40100 m

Find: a and t

(47.5)² = (34.3)² + 2a(40100)

a = 0.0135 m/s²

40100 = ½ (47.5 + 34.3)t

t = 980 s

7 0
3 years ago
Evidence on why we don’t hear solar eruptions on Earth.
sukhopar [10]
Because sound waves don't travel through the vaccume of space. Hope this helped
8 0
3 years ago
Read 2 more answers
Where would you weigh the most?
uranmaximum [27]

Answer:

mars

Explanation:

4 0
3 years ago
Read 2 more answers
A model rocket blasts off from the ground, rising straight upward with a constant acceleration that has a magnitude of 85.0 m/s2
sergey [27]

Answer:

Maximum height attained by the model rocket is 2172.87 m

Explanation:

Given,

  • Initial speed of the model rocket = u = 0
  • acceleration of the model rocket = a\ =\ 85.0 m/s^2
  • time during the acceleration = t = 2.30 s

We have to consider the whole motion into two parts

In first part the rocket is moving with an acceleration of a = 85.0 m/s^2 for the time t = 2.30 s before the fuel abruptly runs out.

Let s_1 be the height attained by the rocket during this time intervel,

s_1\ =\ ut\ +\ \dfrac{1}{2}at^2\\\Rightarrow s_1\ =\ 0\ +\ 0.5\times 85\times 2.30^2\\\Rightarrow s_1\ =\ 224.825\ m

And Final velocity at that point be v

\therefore v\ =\ u\ +\ at\\\Rightarrow v\ =\ 0\ +\ 85.0\times 2.3\\\Rightarrow v\ =\ 195.5\ m/s.

Now, in second part, after reaching the altitude of 224.825 m the fuel abruptly runs out. Therefore rocket is moving upward under the effect of gravitational acceleration,

Let 's_2' be the altitude attained by the rocket to reach at the maximum point after the rocket's fuel runs out,

At that insitant,

  • initial velocity of the rocket = v = 195.5 m/s.
  • a = -g\ =\ -9.81\ m/s^2
  • Final velocity of the rocket at the maximum altitude = v_f\ =\ 0

From the kinematics,

v^2\ =\ u^2\ +\ 2as\\\Rightarrow 0\ =\ u^2\ -\ 2gs_2\\\Rightarrow s_2\ =\ \dfrac{u^2}{2g}\\\Rightarrow s_2\ =\ \dfrac{195.5^2}{2\times 9.81}\\\Rightarrow s_2\ =\ 1948.02\ m

Hence the maximum altitude attained by the rocket from the ground is

s\ =\ s_1\ +\ s_2\ =\ 224.85\ +\ 1948.02\ =\ 2172.87\ m

6 0
3 years ago
an object is moving with a speed of 35 m/s and has a kinetic energy of 1500 J, what is the mass of the object?
Elena-2011 [213]
You'd use the equation kinetic energy=mass*0.5*speed^2
So you'd rearrange this to get mass =kinetic energy /0.5 *speed^2
Which is mass= 1500J/0.5*35^2
=2.44897959183673469........kg
5 0
3 years ago
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