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guajiro [1.7K]
3 years ago
9

In the simulation, both elastic and inelastic collisions take the same amount of time. In which type of collision is the acceler

ation less? Why?
Physics
1 answer:
Verdich [7]3 years ago
5 0

Answer:

its ealstic.

Explanation:

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Acceleration of a body is 10m/s² , what does it mean?​
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It is actually an answer to a question. It has to do with acceleration due to gravity. To understand it more, solve work, energy and time. Search it online. God will help u

7 0
3 years ago
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Radiant energy travels in straight lines until it strikes an object where it can be ______,_____or transmitted
Alborosie
<span>Radiant energy travels in straight lines until it strikes an object where it can be absorbed, reflected or transmitted</span>
7 0
3 years ago
A new interstate highway is being built with a design speed of 120 km/h. For one of the horizontal curves, the radius (measured
nikklg [1K]

Answer:

28.79%

Explanation:

Given

Design Speed, V = 120km/h = 33.33m/s

Radius, R = 300m

Side Friction, Fs = 0.09

Gravitational Constant = 9.8m/s²

Using the following formula, we'll solve the required rate of superelevation.

e + Fs = V²/gR where e = rate

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e = 0.287853367346938

e = 28.79%

Hence, the required rate of superelevation for the curve is calculated as 28.79%

4 0
3 years ago
The switch on the electromagnet, initially open, is closed. What is the direction of the induced current in the wire loop (as se
Marianna [84]

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The induced current is clockwise

6 0
3 years ago
Assume that the length of the magnet is much smaller than the separation between it and the charge. As a result of magnetic inte
faltersainse [42]

Answer:

Assuming that the length of the magnet is much smaller than the separation between it and the charge. As a result of magnetic interaction (i.e., ignore pure Coulomb forces) between the charge and the bar magnet, the magnet will not experience any torque at all - option A

Explanation:

Assuming that the length of the magnet is much smaller than the separation between it and the charge. As a result of magnetic interaction (i.e., ignore pure Coulomb forces) between the charge and the bar magnet, the magnet will not experience any torque at all; the reason being that: no magnetic field is being produced by a charge that is static. Only a moving charge can produce a magnetic effect. And the magnet can not have any torque due to its own magnetic lines of force.

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