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3 years ago

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Two identical batteries, each with an emf of 18 V and an internal resistance of 1 :, are wired in parallel by connecting their p

ositive terminals together and connecting their negative terminals together. The combination is then wired across a 4-: resistor. The current in the 4-: resistor is:

1 answer:

bulgar [2K]3 years ago

8 0

Answer:

I = 4 A

Explanation:

When the batteries are connected in parallel, the voltage is the same as the voltage of each battery, but the internal resistance is less, in general we can assume that the internal resistance is also in parallel.

1 / $r_{eq}$ = 1 / r₁ + 1 / r₂ = 2 / r = 2/1

r_{eq} = 0.5 ohm

The current in the resistor is

V = I R + I r_{eq}

I = V / R + r_{eq}

I = 18 / (4 +0.5)

I = 4 A

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