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3 years ago

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Mathematics

1 answer:

Mkey [24]3 years ago

8 0

Yes it’s school p just mind the mean

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I struggle in math, and occasionally I'll confuse the questions I try to answer

Alex17521 [72]

15X=12X+12
Subtract 12X
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3 years ago

Give the coordinates for point A without using any new variables

Alja [10]

$7.\\A(n+1;\ m)\\\\8.\\A(k;\ 0)$

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3 years ago

Read 2 more answers

HELP ME PLEASE WILL MARK BRAINLIEST

Natali [406]

Answer:

y = 7, x = 7

Step-by-step explanation:

11y + 13 = 90

11y = (90 - 13)

11y = 77

y = 7

2x + 6 = 20 (because 20 is half of 40)

2x = (20 - 6)

2x = 14

x=7

5 0

2 years ago

A 2000-gallon metal tank to store hazardous materials was bought 15 years ago at cost of $100,000. What will a 5,000-gallon tank

harkovskaia [24]

Answer:

The value is $P_o = \$ 561958.9$

Step-by-step explanation:

From the question we are told that

The capacity of the metal tank is $C = 2000 \ gallon$

The duration usage is $t = 15\ years \ ago$

The cost of 2000-gallon tank 15 years ago is $P = \$100,000$

The capacity of the second tank considered is $C_1 = 5,000$

The power sizing exponent is $e = 0.57$

The initial construction cost index is $u_1 = 180$

The new construction after 15 years cost index is $u_2 =600$

Equation for the power sizing exponent is mathematically represented as

$\frac{P_n}{P} = [\frac{C_1}{C} ]^{e}$

=> Here $P_n$ is the cost of 5,000-gallon tank as at 15 years ago

$P_n = [\frac{5000}{2000} ] ^{0.57} * 100000$

$P_n = \$168587.7$

Equation for the cost index exponent is mathematically represented as

$\frac{P_o}{P_n} = \frac{u_2}{u_1}$

Here $P_o$ is the cost of 5,000-gallon tank today

$\frac{P_o}{168587.7} = \frac{600}{180}$

=> $P_o = \frac{600}{180} * 168587.7$

=> $P_o = \$ 561958.9$

8 0

3 years ago

Please answer need fast

agasfer [191]

Answer:

B is the correct ans

please mark brainliest

6 0

2 years ago