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Vlad1618 [11]
3 years ago
14

Match the terms with the correct definitions.

Engineering
1 answer:
arsen [322]3 years ago
7 0
I think answer should be the first one please give me brainlest let me know if it’s correct or not okay thanks bye
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What skills are key to reading comprehension?
ki77a [65]

Ability to recognize words and understand vocabulary

Answer: Option 2.

<u>Explanation:</u>

Reading comprehension is the capacity to process content, comprehend its significance, and to incorporate with what the peruser definitely knows. Capacity to grasp content is affected by perusers' aptitudes and their capacity to process data.

For the students reading comprehension problems frequently include troubles in perceiving and suitably applying foundation information, poor disentangling and word acknowledgment abilities, restricted jargon information, immature understanding familiarity, a not exactly key way to deal with cognizance.

5 0
4 years ago
Carbon dioxide contained in a piston–cylinder device is compressed from 0.3 to 0.1 m3. During the process, the pressure and volu
Lunna [17]

Answer:

W = -6.5 Kpa m^6 (\frac{1}{0.1 m^3}- \frac{1}{0.3 m^3})= -6.5 Kpa m^6 (6.66 m^-3) =-43.33 Kpa m^3 = -43.33 KJ

Explanation:

For this case we know the following info :

V_i = 0.3 m^3 represent the initial volume

V_f = 0.1 m^3 represent the final volume

We know that the pressure and volume are related with the following expression:

P = aV^{-2}= \frac{a}{V^2}

Where a is a constant given a = 6.5 Kpa m^6

And we need to calculate the work associated to this process.

We have a compression, and by definition the work is defined with the following general expression:

W = \int_{V_i}^{V_f} P dV

If we replace the expression for P we got:

W = \int_{V_i}^{V_f} a V^{-2} dV

If we integrate we got:

W = -a (\frac{1}{V}) \Big|_{V_i}^{V_f}

Using the fundamental theorem of calculus we have:

W = -a (\frac{1}{V_f} -\frac{1}{V_i})

And replacing the values we got:

W = -6.5 Kpa m^6 (\frac{1}{0.1 m^3}- \frac{1}{0.3 m^3})= -6.5 Kpa m^6 (6.66 m^-3) =-43.33 Kpa m^3 = -43.33 KJ

5 0
4 years ago
QUESTION 6
Aloiza [94]
It would be 2 Portfolio
3 0
3 years ago
A car crusher has one hydraulic input piston with diameter 2 ft and 6 crushing pistons with diameter 10 feet. If this car needs
IrinaK [193]
Not sure of the answers
4 0
3 years ago
What does WCS stand for? A. Western CAD System B. Worldwide Coordinate Sectors C. World Coordinate System D. Wrong CAD Settings
Ray Of Light [21]

Answer:

The correct answer is C. World Coordinate System

Explanation:

The World Coordinate System has to do with that coordinate system which is fixed in the activities of the CADing. There is a default system in which we can refer to them as soon as we want to manipulate the objects and add new elements.

7 0
4 years ago
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