1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ANTONII [103]
2 years ago
11

What kind of analysis would be conducted to identify project costs?

Engineering
1 answer:
PolarNik [594]2 years ago
5 0

Answer: C. financial analysis

Explanation:

You might be interested in
A tool chest has 650 N weight that acts through the midpoint of the chest. The chest is supported by feet at A and rollers at B.
erica [24]

Answer:

the value of horizontal force P is 170.625 N

the value of horizontal force at P = 227.5 N is that the block moves to right and this motion is due to sliding.

Explanation:

The first diagram attached below shows the free body diagram of the tool chest when it is sliding.

Let start out by calculating the friction force

F_f= \mu N_2

where :

F_f = friction force

\mu = coefficient of friction

N_2 = normal friction

Given that:

\mu = 0.3

F_f = 0.3 N_2

Using the equation of equilibrium along horizontal direction.

\sum f_x = 0

P - F_f = 0

P = 0.3 N_2   ----- Equation (1)

To determine the moment about point B ; we have the expression

\sum M_B  = 0

0 = N_2*70-W*35-P*100

where;

P = horizontal force

N_2 = normal force at support A

W = self- weight of tool chest

Replacing W = 650 N

0 = N_2*70-650*35-100*P

P = \frac{70 N_2-22750}{100} ----- equation (2)

Replacing  \frac{70 N_2-22750}{100}  for P in equation (1)

\frac{70N_2 -22750}{100} =0.3 N_2

N_2 = \frac{22750}{40}N_2 = 568.75 \ N

Plugging the value of N_2 = 568.75 \ N in equation (2)

P = \frac{70(568.75)-22750}{100} \\ \\ P = \frac{39812.5-22750}{100}  \\ \\ P = \frac{17062.5}{100}

P =170.625 N

Thus; the value of horizontal force P is 170.625 N

b)  From the second diagram attached the free body diagram; the free body diagram of the tool chest when it is tipping about point A is also shown below:

Taking the moments about point A:

\sum M_A = 0

-(P × 100)+ (W×35) = 0

P = \frac{W*35}{100}

Replacing 650 N  for W

P = \frac{650*35}{100}

P = 227.5 N

Thus; the value of horizontal force P, when the tool chest tipping about point A is 227.5 N

We conclude that the motion will be impending for the lowest value when P = 170.625 N and when P= 227.5 N

However; the value of horizontal force at P = 227.5 N is that the block moves to right and this motion is due to sliding.

5 0
3 years ago
Do the following addition exercises by translating the numbers into 8-bit 2's complement binary numbers, performing the arithmet
Ganezh [65]

Answer:

I am attaching a file with the solution and explanation as the number character limit is exceeding.

Explanation:

Download docx
8 0
3 years ago
Which of the following are three criteria for creating measurable product attributes?
Vinil7 [7]

Answer:

it A

Explanation:

8 0
3 years ago
Read 2 more answers
Write equations used to calculate the diode reverse saturation current, the voltage at which diode goes into resistive behavior,
laiz [17]

Answer:

Diode equation for reverse saturation current

I_o = A\times e^{\frac{-Eg}{KT}} + B\times e^{\frac{-Eg}{2KT}}  

Voltage at which diode goes into Resistive region:V=-5 volts

Voltage at which high level injection occurs:Va=0.55 volt

Voltage at which avalanche multiplication occurs:V=5volts

Explanation:

we take here forward and reverse 0.7 volt and -5 volt  

As Diode current equation is express as

I_D = I_o \times (e^{\frac{V_D}{\eta V_T}} -1 )   ....................1

here I_D is total current through the diode and I_o is reverse saturated current and V_D is  voltage drop across diode and \eta is idealized factor and V_T is thermal voltage

so here we know that when Bios is forward than

V_D  = V_T     .................2

ans Bios is Reverse than  

V_D  = V_R      ..................3

so here

1.  diode reverse saturation current is express as

I_o = A\times e^{\frac{-Eg}{KT}} + B\times e^{\frac{-Eg}{2KT}}  

and

2. Voltage at which diode go into Reverse behavior will be

V_D  = V_R    = -5 volt

and

3. voltage at which high level injection occur that is

Va = 0.55 volt

and

4. voltage at which avalanche multiplication occurs is

Va = 5 volt

6 0
3 years ago
Click this link to view O*NET’s Work Activities section for Graphic Designers. Note that common activities are listed toward the
bixtya [17]
I can’t click on the link sorry man
8 0
2 years ago
Read 2 more answers
Other questions:
  • given the classes above, what output is produced by the following code? meg[] elements ={new Lois(), new Stewie(), new Meg(), ne
    15·1 answer
  • Describe what V1-V4 is
    10·1 answer
  • Input signal to a controller is​
    9·1 answer
  • 5 cause of a electrical problem​
    6·1 answer
  • Assume, X Company Limited (XCL) is one of the leading 4th generation Life Insurance
    9·2 answers
  • Implement a program that manages shapes. Implement a class named Shape with a method area() which returns the double value 0.0.
    8·1 answer
  • A panel crimper cuts metal True or False
    10·1 answer
  • What should be your strongest tool be for gulding your ethical decisions making process
    5·1 answer
  • 10 properties of metals?<br> ​
    10·2 answers
  • What size resistor would produce a current flow of 5 Amps with a battery voltage of 12.6 volts​
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!