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Kipish [7]
3 years ago
12

What is one thing a person should do to stay safe when exercising

Engineering
2 answers:
elixir [45]3 years ago
7 0
Staying hydrated at all times
KiRa [710]3 years ago
6 0

\ (•◡•) / Hey There!

Answer ➜ ( 6 Different Options To Choose From)

1. Drink Plenty of Water 2. Plan to start slowly and boost your activity level gradually 3. Listen to your body, Hold off on exercise when you're sick or feeling very fatigued 4. Be aware that training too hard or too often can cause overuse injuries like stress fractures, stiff or sore joints and muscles, and inflamed tendons and ligaments 5. If you stop exercising for a while, drop back to a lower level of exercise initially 6. Choose proper workout clothes.

✧☺ Hope this Helps! ✧☺

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state & prove parallelogram law of vector addition &Also determine magnitude &direction of resultant vector.​
ludmilkaskok [199]

Answer:

Parallelogram law of vector addition states that if two vectors are considered to be the adjacent sides of a parallelogram, then the resultant of the two vectors is given by the vector that is diagonal passing through the point of contact of two vectors.

8 0
3 years ago
Air enters the 1 m² inlet of an aircraft engine at 100 kPa and 20° C with a velocity of 180 m/s. Determine: a) The volumetric fl
Shkiper50 [21]

Answer:

a) 180 m³/s

b) 213.4 kg/s

Explanation:

A_1 = 1 m²

P_1 = 100 kPa

V_1 = 180 m/s

Flow rate

Q=A_1V_1\\\Rightarrow Q=1\times 180\\\Rightarrow Q=180\ m^3/s

Volumetric flow rate = 180 m³/s

Mass flow rate

\dot{m}=\rho Q\\\Rightarrow \dot m=\frac{P_1}{RT} Q\\\Rightarrow \dot m=\frac{100000}{287\times 293.15}\times 180\\\Rightarrow \dotm=213.94\ kg/s

Mass flow rate = 213.4 kg/s

3 0
3 years ago
A pipe of 0.3 m outer diameter at a temperature of 160°C is insulated with a material having a thermal conductivity of k = 0.055
Alekssandra [29.7K]

Answer:

Q=0.95 W/m

Explanation:

Given that

Outer diameter = 0.3 m

Thermal conductivity of material

K= 0.055(1+2.8\times 10^{-3}T)\frac{W}{mK}

So the mean conductivity

K_m=0.055\left ( 1+2.8\times 10^{-3}T_m \right )

T_m=\dfrac{160+273+40+273}{2}

T_m=373 K

K_m=0.055\left ( 1+2.8\times 10^{-3}\times 373 \right )

K_m=0.112 \frac{W}{mK}

So heat conduction through cylinder

Q=kA\dfrac{\Delta T}{L}

Q=0.112\times \pi \times 0.15^2\times 120

Q=0.95 W/m

4 0
3 years ago
Water, initially saturated vapor at 4 bar, fills a closed, rigid container. The water is heated until its temperature is 440°C.
lawyer [7]

Answer:

Heat required (q) = 471.19kj/kg

Explanation:

Find attached below solution to problem

7 0
3 years ago
I don’t understand this
blondinia [14]

Answer:

Sorry for the delayed response- Right now I don't have time to give you the answer, but I really want to help so I'll try to phrase it in a easier way to understand things: Basically what you need to do for this problem is find the area of the base of the figure (which means length x width) and then you would simply find the volume of 160cm^{2} by finding the length of each side of the figure, find the length of the figure, find the height of the figure and then find the radius.

Have an amazing day and I hope this can somewhat help :)

7 0
3 years ago
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