Answer:
Step 1: Define the Problem.
Step 2: Do Background Research. .
Step 3: Specify Requirements. .
Step 4: Brainstorm, Evaluate and Choose Solution.
Step 5: Develop and Prototype Solution.
Step 6: Test Solution.
Step 7: Does Your Solution Meet the Requirements?
Step 8: Communicate Results.
can u tell me the definition tho?
palled correctly as “though” which is an alternate form of “although”) at the end is informal usage. It's better placed before “she seems better today
Answer:
The constant here is the study outline
Explanation:
In scientific research, the constant variable is that part/variable of the experiment that does not change or is set not to change. Examples include temperature, environment or height.
Assuming the scenery described in this question is an experiment. All the groups presented are bound by a constant during the experiment. The constant here is the study outline. The study outline provided to the students is not going to change.
NOTE: There could be confusion as regards the answer being the final exam grade but that will be the dependent variable as that will be the outcome of the experiment while the time spent to study will be the independent variable.
Los MOSFET de potencia son dispositivos de conducción unipolar. En ellos, los niveles de corriente conducida no están asociados al aumento de la concentración de portadores minoritarios, que luego son difíciles de eliminar para que el dispositivo deje de conducir.
Answer:
A single- shear pin connection.
Explanation:
Answer:
Heat losses by convection, Qconv = 90W
Heat losses by radiation, Qrad = 5.814W
Explanation:
Heat transfer is defined as the transfer of heat from the heat surface to the object that needs to be heated. There are three types which are:
1. Radiation
2. Conduction
3. Convection
Convection is defined as the transfer of heat through the actual movement of the molecules.
Qconv = hA(Temp.final - Temp.surr)
Where h = 6.4KW/m2K
A, area of a square = L2
= (0.25)2
= 0.0625m2
Temp.final = 250°C
Temp.surr = 25°C
Q = 64 * 0.0625 * (250 - 25)
= 90W
Radiation is a heat transfer method that does not rely upon the contact between the initial heat source and the object to be heated, it can be called thermal radiation.
Qrad = E*S*(Temp.final4 - Temp.surr4)
Where E = emissivity of the surface
S = boltzmann constant
= 5.6703 x 10-8 W/m2K4
Qrad = 5.6703 x 10-8 * 0.42 * 0.0625 * ((250)4 - (25)4)
= 5.814 W
