A wave in which particles of matter vibrate at right angles to the direction

Calculate the density in g/ml of 2.0 L of gasoline that weighs 1.32 kg

sveta [45]

Answer: 0.66 g/mL

Explanation: The formula for density is d= m/v where m=mass and v=volume.

The mass was given in the problem, m= 1.32kg

The volume was also given in the problem, v= 2.0L

d= m/v ---> d= 1.32kg/2.0L ---> d=0.66kg/L

The problem calls for the answer to be written in g/mL, so we must convert the units. 1 kg contains 1000g and 1 L contains 1000 mL.

1000g/1000mL = 1 so the units change but the 0.66 does not. Therefore, your answer is 0.66g/mL (Two significant figures because 2.0 only has 2 significant figures).

4 0

2 years ago

Rank the following transitions in a hydrogen atom in order of increasing wavelength of electromagnetic radiation that could prod

Dmitrij [34]

Answer:

n=2 to n=4 < n=6 to n=8 < n=10 to n=12 < n=14 to n=16

Explanation:

According to Neils Bohr, electrons in an atom are found in specified energy levels. Transitions are possible from one energy level to another when the electron receives sufficient energy usually in the form of a photon of electromagnetic radiation of appropriate frequency and wavelength. The energy of this photon corresponds to the energy difference between the two energy levels. Thus the higher the energy difference between energy levels, the greater the energy of the photon required to cause the transition and the shorter the wavelength of the photon.

High energy photons have a very short wavelength. It should be noted that as n increases, the energy of successive energy levels decreases and transitions between them now occurs at longer wavelengths. Hence, the highest energy and shortest wavelength of photons are required for transition involving lower values of n because such electrons are closer to the nucleus and are more tightly bound to it than electrons found at a greater distance from the nucleus.

Hence transition involving electrons at higher energy levels occur at a longer wavelength compared to transition involving electrons closer to the nucleus. This is the basis for the arrangement of wavelengths required to effect the various electronic transitions shown in the answer.

3 0

3 years ago

C. Is curium (Cm) radioactive or not radio active? Why? <br><br> Why is curium radioactive?

Anit [1.1K]

Answer:

radioactive

Explanation:

u do the why here is one

4 0

3 years ago

Which species is oxidized in the reaction below? al2o3(s) 3 co(g) → 2 al(s) 3 co2(g)

Elza [17]

Al species is oxidized in the reaction below al2o3(s) 3 co(g) → 2 al(s) 3 co2(g by oxidation

The reaction brought on by coming into touch with oxygen molecules is known as oxidation. These materials can be non-metals like live tissues or metals. Technically speaking, oxidation is the loss of one electron during the phase of interaction between two or more atoms.

Initially, the word "oxidation" was used to refer to chemical processes in which an element reacts with oxygen. An illustration of this is the oxidation of magnesium in the formation of magnesium oxide when magnesium metal and oxygen react.

The biological oxygen demand (BOD) of wastewater is decreased after oxidation, which also lessens some contaminants' toxicity. Some contaminants undergo this treatment and are transformed into carbon dioxide, water, and biosolids. Disinfection is commonly accomplished using chemical oxidation.

To learn more about oxidation please visit-
brainly.com/question/376562
#SPJ4

8 0

2 years ago

Suppose a 500.mL flask is filled with 1.0mol of CO, 1.5mol of H2O and 0.70mol of CO2. The following reaction becomes possible: +

valentina_108 [34]

Answer:

[CO] = 0.62 M

Explanation:

Step 1: Data given

Volume of the flask = 500 mL

Number of moles CO = 1.0 moles

Number of moles H2O = 1.5 moles

Number of moles CO2 = 0.70 moles

The equilibrium constant K for this reaction is 3.80

Step 2: The balanced equation

CO(g) + H2O(g) ⇆ CO2(g) +H2(g)

Step 3: Calculate the initial concentrations

Concentration = moles / volume

[CO] = 1.0 moles / 0.500 L = 2.0 M

[H2O] = 1.5 moles / 0.500 L = 3.0 M

[CO2] = 0.70 moles / 0.500 L = 1.4 M

[H2] = 0M

Step 4: The concentration at the equilibrium

For 1 mol CO we have 1 mol H2O to produce 1 mol CO2 and 1 mol H2

[CO] = 2.0 -X M

[H2O] = 3.0 - X M

[CO2] =1.4 + X M

[H2] = X M

Step 5: Define Kc

Kc = [CO2][H2]/ [CO][H2O]

3.80 = (1.4 + X) * X / ((2.0 - X)*3.0 -X))

X = 1.38

[CO] = 2.0 -1.38 = 0.62 M

[H2O] = 3.0 - 1.38 = 1.62 M

[CO2] =1.4 + 1.38 M = 2.78

[H2] = 1.38 M

Kc = (2.78*1.38) / (0.62*1.62)

Kc = 3.8

[CO] = 0.62 M

8 0

3 years ago