Answer:
1.13×10^25 molecules of water.
Explanation:
Equation of the reaction;
C8H18(g) + 25/2 O2 (g) -------> 8CO2(g) + 9H2O(l)
It is important to first put down the balanced reaction equation. It is not possible to solve any problem on stoichiometric relationship without a balanced reaction equation. Once the equation is obtained, we can now proceed with other steps in the solution of the problem.
From the reaction equation, 1 mole of C8H18 produces 9 moles of water
1 mole of C8H18 occupies 22.4L volume while 1 mole of water contains 6.02×10^23 molecules of water
Hence
22.4 L of C8H18 produces 9(6.02×10^23) molecules of water
46.72 L of C8H18 will produce 46.72 L × 9(6.02×10^23) molecules of water/22.4 L
= 113×10^23 or 1.13×10^25 molecules of water.
Answer:
480 L
Explanation:
In order to solve this question, you should be familiar with gas laws. (I will attach a picture showing all of them under my answer.) In this question in particular, however, we only need Charles's Law because we're dealing with temperature and volume.
As we can see, Charles's Law is:
or, initial volume over initial temperature equals final volume over final temperature.
In this question, 60 L is our <u>initial volume,</u> and 0.5 K is our <u>initial temperature</u> (K being Kelvin). We are only given 4 K as our <u>final temperature</u>. We are asked to solve for the <u>final volume</u>. Let's set up the equation and solve for 
:
--------------------------------------------------------------------------------------------------------------
(60) / (0.5) = / (4)
↓
120 = / 4
×4 ×4
↓
= 480 L
--------------------------------------------------------------------------------------------------------------
There's our answer! Feel free to comment if you have any questions about my answer :)
Answer:
121.63 g/mol
Explanation:
Sr(OH) 2 = Strontium Hydroxide
Answer:
T2 =21.52°C
Explanation:
Given data:
Specific heat capacity of sample = 1.1 J/g.°C
Mass of sample = 385 g
Initial temperature = 19.5°C
Heat absorbed = 885 J
Solution:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = Final temperature - initial temperature
885J = 385 g× 1.1 J/g.°C×(T2 - 19.5°C )
885 J = 423.5 J/°C× (T2 - 19.5°C )
885 J / 423.5 J/°C = (T2 - 19.5°C )
2.02°C = (T2 - 19.5°C )
T2 = 2.02°C + 19.5°C
T2 =21.52°C
