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Pachacha [2.7K]
3 years ago
11

Sn4+(aq) + 2e− → sn2+(aq)which term best describes this reaction?ionizationneutralizationoxidationreduction

Chemistry
1 answer:
Yakvenalex [24]3 years ago
4 0

Answer:

Reduction

Explanation:

Gaining electrons means reduction. When the electrons are on the reactant side of the reaction, they are added to the other reactant. This indicates that the Sn^4+ is gaining electrons and is therefore reduced (reduction).

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Equal amounts of N2 and O2 are added, under certain conditions, to a closed container. Which changes occur in the reverse reacti
geniusboy [140]
1) The forward reaction is N2 (g) + O2 (g)  → 2NO

(that reaction requires special contitions because at normal pressures and temperatures N2 and O2 do not react to form another compound.

2) The equiblibrium equation is

  N2 (g) + O2 (g)  ⇄ 2NO

3) Then, the reverse reaction is

2NO → N2(g) + O2(g)

Answer: 2NO → N2(g) + O2(g)
4 0
3 years ago
Consider the following system at equilibrium:
alexgriva [62]

Answer:

A - Increase (R), Decrease (P), Decrease(q), Triple both (Q) and (R)

B - Increase(P), Increase(q), Decrease (R)

C - Triple (P) and reduce (q) to one third

Explanation:

<em>According to Le Chatelier principle, when a system is in equilibrium and one of the constraints that affect the rate of reaction is applied, the equilibrium will shift so as to annul the effects of the constraint.</em>

P and Q are reactants, an increase in either or both without an equally measurable increase in R (a product) will shift the equilibrium to the right. Also, any decrease in R without a corresponding decrease in either or both of P and Q will shift the equilibrium to the right. Hence, Increase(P), Increase(q), and Decrease (R) will shift the equilibrium to the right.

In the same vein, any increase in R without a corresponding increase in P and Q will shift the equilibrium to the left. The same goes for any decrease in either or both of P and Q without a counter-decrease in R will shift the equilibrium to the left. Hence, Increase (R), Decrease (P), Decrease(q), and Triple both (Q) and (R) will shift the equilibrium to the left.

Any increase or decrease in P with a commensurable decrease or increase in Q (or vice versa) with R remaining constant will create no shift in the equilibrium. Hence, Triple (P) and reduce (q) to one third will create no shift in the equilibrium.

6 0
3 years ago
What is the concentration of the murexide soution with a transmittance of 28.65%. (molar absorptivity = 3847)
Ainat [17]

Answer:

The concentration of the murexide solution is 0.0000745 M

Explanation:

From Beer-Lambert's law,

A = εlc

A = Absorbance = 28.65% = 0.2865

ε = molar absorptivity = 3847 M/cm

l = path length = 1cm

c = concentration in mol/L = ?

c = A/εl = 0.2865/(3847×1) = 0.0000745 mol/L

Hope this Helps!

6 0
3 years ago
_____ is the degree of attraction of one atom for the valence electrons of another atoms. Electronegativity Ionization energy Co
yan [13]
<span>Electronegativity maybe.......</span>
4 0
3 years ago
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How many moles of C are needed to react with 0.460 mole SO2 ? Equation: 5C(s)+2SO2(g)→CS2(l)+4CO(g)
stepan [7]

Answer:

12345678909ygtufyghkkgjfjvhbkjn,bhmgncfxcgvhbm

Explanation:

3 0
3 years ago
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