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Pachacha [2.7K]
3 years ago
11

Sn4+(aq) + 2e− → sn2+(aq)which term best describes this reaction?ionizationneutralizationoxidationreduction

Chemistry
1 answer:
Yakvenalex [24]3 years ago
4 0

Answer:

Reduction

Explanation:

Gaining electrons means reduction. When the electrons are on the reactant side of the reaction, they are added to the other reactant. This indicates that the Sn^4+ is gaining electrons and is therefore reduced (reduction).

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A monatomic ideal gas that is initially at 1.50 * 105 Pa and has a volume of 0.0800 m3 is compressed adiabatically to a volume o
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Answer:

300000Pa or 3×10^5 Pa

Explanation:

Since the problem involves only two parameters of volume and pressure, the formula for Boyle's law is suitably used.

Using Boyle's law

P1V1 = P2V2

P1 is the initial pressure = 1.5×10^5Pa

V1 is the initial volume = 0.08m3

P2 is the final pressure (required)

V2 is the final volume = 0.04 m3

From the formula, P2 = P1V1/V2

P2 = 1.5×10^5 × 0.08 ÷ 0.04

= 300000Pa or 3×10^5 Pa.

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3 years ago
A breeder nuclear reactor is a reactor in which nonfissile U-238 is converted into fissile Pu-239. The process involves bombardm
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<u>Answer:</u> The nuclear equations for the given process is written below.

<u>Explanation:</u>

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_Z^A\textrm{X}\rightarrow _{Z+1}^A\textrm{Y}+_{-1}^0\beta

The chemical equation for the first beta decay process of _{92}^{239}\textrm{U} follows:

_{92}^{239}\textrm{U}\rightarrow _{93}^{239}\textrm{Np}+_{-1}^0\beta

The chemical equation for the second beta decay process of _{93}^{239}\textrm{Np} follows:

_{93}^{239}\textrm{Np}\rightarrow _{94}^{239}\textrm{Pu}+_{-1}^0\beta

Hence, the nuclear equations for the given process is written above.

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Answer:

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Explanation:

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<em><u>please mark me brainliest</u></em>

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