How do you do this problem?

kodGreya [7K]

Answer:

$y=-2\,(x+3)^2-3$

Step-by-step explanation:

Notice that they are asking you to write the equation of the parabola in vertex form, that is using the coordinates of the vertex $(x_v,y_v)$ in the expression:

$y-y_v=a\,(x-x_v)^2\\y=a\,(x-x_v)^2+y_v$

we can start by directly replacing the given vertex coordinates (-3, -3) in the expression, and then using the extra info on the point the parabola goes through in order to find the parameter $a$ :

$y=a\,(x-x_v)^2+y_v\\y=a\,(x+3)^2+(-3)\\y=a\,(x+3)^2-3\\-5=a\,(-2+3)^2-3\\-5=a\,(1)-3\\a=-5+3\\a=-2$

So, now we can write the full expression for the parabola:

$y=a\,(x+3)^2-3\\y=-2\,(x+3)^2-3$

8 0

3 years ago

Given: RW ≅ WT; UW ≅ WS Prove: RSTU is a parallelogram. Identify the steps that complete the proof.

JulijaS [17]

Identify the steps that complete the proof.

♣ = ✔ vertical angles theorem

♦ = ✔ SAS

♠ = ✔ CPCTC

7 0

3 years ago

Read 2 more answers

A bird was sitting 16 feet from the base of an oak tree and flew 20 feet to reach the top of the tree. How tall is the tree?

Eddi Din [679]

Given:

A bird was sitting 16 feet from the base of an oak tree and flew 20 feet to reach the top of the tree.

To find:

The length of the tree.

Solution:

A bird was sitting 16 feet from the base of an oak tree.

Vertical distance between bird and base = 16 feet

Then the bird flew 20 feet to reach the top of the tree.

Now, the vertical distance between bird and base = (16+20) feet

So, length of the oak tree is it the sum of 16 feet and 20 feet.

$\text{Length of the oak tree}=16+20$ feet

$\text{Length of the oak tree}=36$ feet

Therefore, the length of the oak tree is 36 feet.

5 0

3 years ago

A sample of 11 students using a Ti-89 calculator averaged 31.5 items identified, with a standard deviation of 8.35. A sample of

lina2011 [118]

Answer:

We reject H₀, with CI = 90 % we can conclude that the mean numbers of times identified with Ti-84 does not exceed that of the Ti-89 by more than 1,80

Step-by-step explanation:

Ti-89 Calculator

Sample mean x = 31,5

Sample standard deviation s₂ = 8,35

Sample size n₂ = 11

Ti-84 Calculator

Sample mean y = 46,2

Sample standard deviation s₁ = 9,99

Sample size n₁ = 12

t(s) = ( y - x - d ) / √s₁²/n₁ + s₂²/n₂

t(s) = 12,9 / √(99,8/12) + (69,72/11)

t(s) = 12,9 / √8,32 + 6,34

t(s) = 12,9 / 3,83

t(s) = 3,37

Test Hypothesis

Null Hypothesis H₀ y - x > 1,80

Altenative Hypothesis Hₐ y - x ≤ 1,80

We have a t(s) = 3,37

We need to compare with t(c) critical value for

t(c) α; n₁ +n₂-2 df = 12 +11 -2 df = 21

If we choose CI = 95 % then α = 5 % α = 0,05

From t-student table

t(c) = 1,72

t(s) = 3,37

t(s) >t(c)

t(s) is in the rejection region therefore we accept Hₐ with CI = 95 %

8 0

3 years ago

An 8-sided fair die is rolled twice and the product of the two numbers obtained when the die is rolled two times is calculated.

ELEN [110]

Answer:

(a)

$\left[\begin{array}{ccccccccc} &1&2&3&4&5&6&7&8\\1&1&2&3&4&5&6&7&8\\2&2&4&6&8&10&12&14&16\\3&3&6&9&12&15&18&21&24\\4&4&8&12&16&20&24&28&32\\5&5&10&15&20&25&30&35&40\\6&6&12&18&24&30&36&42&48\\7&7&14&21&28&35&42&49&56\\8&8&16&24&32&40&48&56&64\end{array}\right]$

(b)

(i)probability that the product of the two numbers is a prime number=7/64

(ii)probability that the product of the two numbers is not a perfect square=56/64

(iii)probability that the product of the two numbers is a multiple of 5 =15/64

(iv)probability that the product of the two numbers is Less than or equal to 21 =40/64

(v) probability that the product of the two numbers is divisible by 4 or 6 =42/64

Step-by-step explanation:

(a) 8-sided fair die implies each die can have outcomes 1,2,3,4,5.6,7,8 with equal chances.

To draw the possibility diagram of the product of the two numbers appearing on the die in each throw, we put the outcomes of both dies side by side and find the product of possible outcomes.

(b) probability= Number of outcome / Total number of outcomes

(i)probability that the product of the two numbers is a prime number=8/64=1/8

based on sample space, the prime numbers are 2,2,3,3,5,5,7,7

(ii)probability that the product of the two numbers is not a perfect square=56/64=7/8

based on sample space, only 1,4,9,16,25,36,49,64 are perfect square

(iii)probability that the product of the two numbers is a multiple of 5 =15/64

(iv)probability that the product of the two numbers is Less than or equal to 21 =40/64=5/8

(v) probability that the product of the two numbers is divisible by 4 or 6 =42/64=21/32

6 0

3 years ago

How do you do this problem?​

How do you do this problem?