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3 years ago

Find the area of a square if it’s sides measure 2+2/3URGENT

Mathematics

2 answers:

Anon25 [30]3 years ago

4 0

Answer:

1.33333333333

Step-by-step explanation:

because length times with

Vesnalui [34]3 years ago

4 0

Answer:

The area of a square is s^2 or s*s where s is the length of a side, so:

(2+2)/3 * (2+2)/3

4/3 * 4/3

(4/3)^2

Which equals about: 1.77

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A=Bxt+C

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3 years ago

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solong [7]

Use explanation in picture

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mr_godi [17]

Answer:

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3 years ago

A coordinate plane with a line passing through points (1, 2) and (4, 4)

Kobotan [32]

A straight line is represented by a linear equation given below.

The points are given as (1, 2) and (4, 4).

Start by calculating the slope (m)

$m=\frac{y_2-y_1}{x_2-x_1}$

So, we have

$m=\frac{4-2}{4-1} \\m=\frac{2}{3}$

<h3>What is the slope-intercept form of the line?</h3>

The equation in slope-intercept form is then calculated as:

$y=m(x-x_1)+y_1$

So, we have:

$y=\frac{2}{3}(x-1)+2\\ \\y=\frac{2}{3}(x-4)+4\\$

Expand

$y=\frac{2}{3}(x-1)+2\\ y=\frac{2}{3} x-\frac{2}{3}+2$

Take LCM

$y=2/3x+4/3$

Multiply through by 3

3y=2x+4

So, the possible equations are:

. $3y=2x+4\\y=\frac{2}{3}x+\frac{4}{3} \\y=\frac{2}{3}(x-1)+2\\y=\frac{2}{3}(x-4)+{4}$

To learn more about linear equations visit:

brainly.com/question/11897796

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2 years ago

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