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4 years ago

Melting wax

2 answers:

5 0

The answer is C: Chemical Change. Example: Chemical change is like burning fire wood. Physical change is like a pipe rusting. Thank you have a nice day

MaRussiya [10]4 years ago

3 0

It would have to be c because it is a chemical change. your welcome!!!!!

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Seema could easily hear her echo when she shouted in her schools multipurpose hall. Later she shouted in the same manner in her

nirvana33 [79]

Answer with Explanation:

Echo depends on "how sound waves are reflected back." A hard object, like the walls of the multipurpose hall, reflects sound waves well; thus, Seema could easily hear her echo. In addition to this, the walls of the hall are also smooth and this further allows the sound waves to bounce. On the other hand, soft objects like bed cushions in Seema's room absorbs sound. This prevents the sound waves from being reflected. In addition to this, the sound waves have hard time bouncing because there are many objects in Seema's room.

4 0

3 years ago

A 50 g sample of an unknown metal is heated to 90.0C. It is placed in a perfectly insulated container along with 100 g of water

Scrat [10]

Answer:

0.64 J/g°C

Explanation:

Using the formula;

Q = m × c × ∆T

Where;

Q = amount of heat

m = mass (g)

c = specific heat capacity

∆T = change in temperature (°C)

In this case:

Q (water) = - Q (metal)

mc∆T (water) = - mc∆T (metal)

According to the information in this question,

For water; m = 100g, c = 4.18J/g°C, ∆T = (25°C - 20°C)

For metal; m = 50g, c =?, ∆T = (25°C - 90°C)

mc∆T (water) = - mc∆T (metal)

100 × 4.18 × (25°C - 20°C) = - {50 × c × (25°C - 90°C)}

100 × 4.18 × 5 = - {50 × c × -65}

2090 = -{-3250c}

2090 = 3250c

c = 2090/3250

c = 0.643

c = 0.64J/g°C

7 0

3 years ago

Read 2 more answers

Find the magnitude of the electric field at a point 0.35 m to the right of a sphere of a charge of 1.20×10^−6 C.

frozen [14]

https://mrsstowell.weebly.com/uploads/5/1/4/6/51460659/hsav_riverdale.k12.wi.us_20160330_092123.pdf

6 0

3 years ago

A musical chord consists of several notes, each formed by a sound wave of a different frequency. The three graphs show the patte

sweet [91]

Answer:

If a chord had notes with frequencies of 100, 1,000, and 6,000 Hz, the basilar membran would vibrate at multiple positions, with peaks at A, B, and C.

Explanation:

3 0

3 years ago

A thin, uniform metal bar, 2.00 m long and weighing 90.0 N, is hanging vertically from the ceiling by a frictionless pivot. Sudd

matrenka [14]

Answer:

(a) The "angular speed" is 5.88 rad/s.

Explanation:

Given values,

The length of the bar is L = 2m

The weight of the bar is w = 90 N

The metal bar is hanging vertically from the ceiling by a frictionless pivot

The mass of the ball is m = 3kg

The distance between the ceiling and the ball is d = 1.5m

$\text { The "initial speed of the ball" is } V_{i}=10 \mathrm{m} / \mathrm{s}$

$\text { The "final speed of the ball" is } V_{f}=6 \mathrm{m} / \mathrm{s}$

(a) Calculating the angular speed:

$W_{\mathrm{f}}=\left(3 \mathrm{mg} \mathrm{d} \frac{V_{i}+V_{f}}{w l^{2}}\right)$

$W_{f}=\left(3 \times 3 \times 9.8 \times 1.5 \times \frac{10+6}{90 \times 2^{2}}\right)$

$W_{f}=\frac{2116.8}{360}$

$\mathrm{W}_{\mathrm{f}}=5.88 \mathrm{rad} / \mathrm{s}$

The angular speed is 5.88 rad/s.

(b) The "angular momentum" is conserved because the torque is not exerted by "the pivot" on the system about the "axis of rotation" but the "linear momentum" is not conserved because "the pivot" exerts a "vertical" and a "horizontal force" on the system during the collision.

8 0

4 years ago