Question

A silver block, initially at 55.6∘C, is submerged into 100.0 g of water at 24.5∘C in an insulated container. The final temperature of the mixture upon reaching thermal equilibrium is 27.3∘C. The specific heat capacities for water and silver are Cs,water=4.18J/(g⋅∘C) and Cs,silver=0.235J/(g⋅∘C).
What is the mass of the Silver block?

Answer 1

Answer:

$m_{Ag} = 175.987\,g$

Explanation:

The First Law of Thermodynamics helps to determine the mass of the silver block:

$m_{Ag}\cdot \left(0.235\,\frac{J}{g\cdot ^{\textdegree}C} \right)\cdot (55.6^{\textdegree}-27.3^{\textdegree}C) = (100\,g)\cdot \left(4.18\,\frac{J}{g\cdot ^{\textdegree}C} \right)\cdot (27.3^{\textdegree}C-24.5^{\textdegree}C)$

The mass of the silver block is:

$m_{Ag} = 175.987\,g$