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zaharov [31]
3 years ago
5

Help mi out plz..... solve using matrix method​

Mathematics
1 answer:
HACTEHA [7]3 years ago
5 0

Answer:

x = \frac{22}{7}

y = \frac{3}7}

Step-by-step explanation:

2x-3y=5\\5x=4y=14\\\\\left[\begin{array}{cc}2&-3\\5&-4\\\end{array}\right] \left[\begin{array}{c}x\\y\\\end{array}\right] =\left[\begin{array}{c}5\\14\\\end{array}\right]

Let A = \\\left[\begin{array}{cc}2&-3\\5&-4\\\end{array}\right]

The inverse of A multiplied by A = the identity matrix \left[\begin{array}{cc}1&0\\0&1\\\end{array}\right]

Inverse of A = \frac{1}{detA} \left[\begin{array}{ccc}-4&3\\-5&2\\\end{array}\right]

detA = ad - bc = -8 - - 15 = 7

Inverse of A = \left[\begin{array}{cc}\frac{-4}{7} &\frac{3}{7} \\\frac{-5}{7} &\frac{2}{7}\\\end{array}\right]

\left[\begin{array}{ccc}x\\y\\\end{array}\right] = \left[\begin{array}{cc}\frac{-4}{7} &\frac{3}{7} \\\frac{-5}{7} &\frac{2}{7}\\\end{array}\right] \left[\begin{array}{ccc}5\\14\\\end{array}\right] = \left[\begin{array}{ccc}\frac{22}{7} \\\frac{3}{7} \\\end{array}\right]

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