97 is a prime number. So it's only factors are 1 and 97.
Answer:
the answer for this is:
subtract 7 from 4 to get -3
you then have 2^-3
remove the negative exponent by rewriting as 1/(2^3)
Step-by-step explanation:
Here you go this took me time
Answer:
f(4)=-3
Step-by-step explanation:
f(1)=2
f(n)=f(n-1)^2-n
If n=2
f(2)=f(2-1)^2-2
f(2)=f(1)^2-2
f(2)=2^2-2
f(2)=4-2
f(2)=2
If n=3
f(3)=f(3-1)^2 - 3
f(3)=f(2)^2 - 3
f(3)=2^2-3
f(3)=4-3
f(3)=1
if n=4
f(4)=f(4-1)^2 - 4
f(4)=f(3)^2 - 4
f(4)=1^2 - 4
f(4)=1-4
f(4)=-3
Answer:
= 35 - 13n
Step-by-step explanation:
Assuming you require the n th term formula
The n th term of an arithmetic sequence is
= a₁ + (n- 1)d
where a₁ is the first term and d the common difference
Here a₁ = 22 and d = - 13, thus
= 22 - 13(n - 1) = 22 - 13n + 13 = 35 - 13n
