For this standard for, a = -1, b = 0 and c = 18.
In order to find this, you must first multiply the two parenthesis by each other.
(5 + x)(5 - x)
25 + 5x - 5x - x^2
25 - x^2
Now we need to set it equal to the other side and solve for 0.
25 - x^2 = 7 ----> subtract 7 from both sides.
18 - x^2 = 0 -----> now readjust the order
-x^2 + 18 = 0
So, once we've reached here, the a value is always the coefficient of the x^2 term (-1), b is the value of the coefficient of the x term (0) and c is the constant (18).
<h3>
Answer: 1/1989</h3>
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Explanation:
1/6 is the probability of rolling a '3' since there is one side we want out of 6 total.
The probability of getting an ace is 4/52 because there are 4 aces out of 52 cards total.
If that card isn't put back, then we have 52-1 = 51 cards left. That means the probability of drawing a black 2 is 2/51. The numerator 2 has nothing to do with the card value of '2'. It has to do with the fact we have 2 black cards (2 of spades, 2 of clubs) out of 51 left over.
We multiply the fractions to get the final answer
(1/6)*(4/52)*(2/51)
(1*4*2)/(6*52*51)
8/15912
1/1989
When using a calculator, we can see that,
1/1989 = 0.0005 = 0.05%
There is a very small chance of all three events happening at the same time.
Answer:
5,698,80
Step-by-step explanation:
this is easy if you paid attention in class
Multiply like such:
((a^2) -36) x 6 3 x (a^2) - 7a + 6
----------- and ----------
((a^2) -36) x (a^2) - 7a + 6 (a^2)-36 x (a^2) - 7a + 6
to get
6 3
--------------- x -----------
( a - 1 ) ( a - 6 ) ( a - 6 ) (a + 6 )
Which totals : (This is the answer)
18
--------------
( a - 6 )^2 ( a + 6 ) ( a - 1 )
I tried my best, if this isnt right sorry :P
