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3 years ago

Sean tried to drink a slushy as fast as he could. He drank 5 milliliters of slushy each second and finished all

Mathematics

1 answer:

castortr0y [4]3 years ago

6 0

Answer:

graph like this:

Step-by-step explanation:

First, in 5 seconds, we know that he drinks 25 mL of slushy. We know this because 1 second is 5 mL, so 5 seconds is 25 mL. So, your graph should be going from the 5 second to 25 mL mark, then the 10 second and 50 mL mark, then the 15 mL and 75 mL mark, and so on.

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PLEASE I NEED THIS!! Which quadrilateral(s) have the same attributes as a rhombus

uranmaximum [27]

Answer:

The correct answer is square and parallelogram

Explanation:

If you turn the rhombus around it will turn into a square

8 0

3 years ago

What is the period of the function y=3/2con(3/5x)+5

jeyben [28]

Answer:

$y = \frac{3}{2} cot( \frac{3x}{5} ) + 5 \\ \\ \pi \div \frac{3}{5} \\ \ \\ = \frac{5\pi}{3} is \: period$

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3 years ago

A rectangular Corn Hole area at the Recreation Center has a width of 5 feet and a length of 10 feet. If

inysia [295]

Answer:

2 feet

Step-by-step explanation:

Let

x ----> the uniform amount added to each side

we know that

The algebraic expression that represent this situation is

$(5+x)(10+x)=84$

solve for x

Apply distributive property

$50+ 5x+10x+x^2=84\\x^2+15x-34=0$

solve the quadratic c equation

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$x^2+15x-34=0$

$a=1\\b=15\\c=-34$

substitute in the formula

$x=\frac{-15\pm\sqrt{15^{2}-4(1)(-34)}} {2(1)}$

$x=\frac{-15\pm\sqrt{361}} {2}$

$x=\frac{-15\pm19} {2}$

$x=\frac{-15\pm19} {2}=2$

$x=\frac{-15\pm19} {2}=-17$

therefore

The solution is x=2 ft

8 0

3 years ago

a stone falls from a ledge and takes 8 seconds to the hit the ground. the stone has an original velocity of 0 m/s. how tall is t

Verizon [17]

Using equation of motion.

S = ut + (1/2)gt²

Where S = Height, t = time, g = acceleration due to gravity = 9.8 m/s²

time, t = 8 seconds

Since it was dropped from height, initial velocity, u = 0

S = 0*t + (1/2)gt²

S = (1/2)gt²

S = (1/2)*9.8*8² = 4.9 * 8 * 8 = 313.6

Therefore the ledge is 313.6 m tall.

6 0

3 years ago

Read 2 more answers

Replace ? with an expression that will make the equation valid.

AlexFokin [52]

Answer:

4x³

Step-by-step explanation:

d/dx ln(x⁴ + 7) = 1/(x⁴ + 7) × _?

To obtain the missing expression, let us simplify d/dx ln(x⁴ + 7). This can be obtained as follow:

Let y = ln (x⁴ + 7)

Let u = (x⁴ + 7)

Therefore,

ln(x⁴ + 7) = ln u

Thus,

y = ln u

dy/du = 1/u

Next, we shall determine du/dx. This is illustrated below:

u = (x⁴ + 7)

du/dx = 4x³

Finally, we shall determine dy/dx of ln (x⁴ + 7) as follow:

dy/dx = dy/du × du/dx

dy/du = 1/u

du/dx = 4x³

dy/dx = 1/u × 4x³

But:

u = (x⁴ + 7)

Therefore,

dy/dx = 1/(x⁴ + 7) × 4x³

Thus, the missing expression is 4x³

6 0

3 years ago