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kodGreya [7K]
3 years ago
5

Sean tried to drink a slushy as fast as he could. He drank 5 milliliters of slushy each second and finished all

Mathematics
1 answer:
castortr0y [4]3 years ago
6 0

Answer:

graph like this:

Step-by-step explanation:

First, in 5 seconds, we know that he drinks 25 mL of slushy. We know this because 1 second is 5 mL, so 5 seconds is 25 mL. So, your graph should be going from the 5 second to 25 mL mark, then the 10 second and 50 mL mark, then the 15 mL and 75 mL mark, and so on.

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PLEASE I NEED THIS!! Which quadrilateral(s) have the same attributes as a rhombus
uranmaximum [27]

Answer:

The correct answer is square and parallelogram

Explanation:

  • If you turn the rhombus around it will turn into a square
8 0
3 years ago
What is the period of the function y=3/2con(3/5x)+5
jeyben [28]

Answer:

y =  \frac{3}{2} cot( \frac{3x}{5} ) + 5 \\  \\  \pi \div \frac{3}{5} \\  \  \\  =  \frac{5\pi}{3} is \: period

6 0
3 years ago
A rectangular Corn Hole area at the Recreation Center has a width of 5 feet and a length of 10 feet. If
inysia [295]

Answer:

2 feet

Step-by-step explanation:

Let

x ----> the uniform amount added to each side

we know that

The algebraic expression that represent this situation is

(5+x)(10+x)=84

solve for x

Apply distributive property

50+ 5x+10x+x^2=84\\x^2+15x-34=0

solve the quadratic c equation

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}

in this problem we have

x^2+15x-34=0  

so

a=1\\b=15\\c=-34

substitute in the formula

x=\frac{-15\pm\sqrt{15^{2}-4(1)(-34)}} {2(1)}

x=\frac{-15\pm\sqrt{361}} {2}

x=\frac{-15\pm19} {2}

x=\frac{-15\pm19} {2}=2

x=\frac{-15\pm19} {2}=-17

therefore

The solution is x=2 ft

8 0
3 years ago
a stone falls from a ledge and takes 8 seconds to the hit the ground. the stone has an original velocity of 0 m/s. how tall is t
Verizon [17]
Using equation of motion.

S = ut + (1/2)gt²

Where S = Height, t = time, g = acceleration due to gravity = 9.8 m/s²

time, t = 8 seconds 

Since it was dropped from height, initial velocity, u = 0

S = 0*t + (1/2)gt²

S = (1/2)gt²

S = (1/2)*9.8*8²  = 4.9 * 8 * 8 =  313.6

Therefore the ledge is 313.6 m tall.
6 0
3 years ago
Read 2 more answers
Replace ? with an expression that will make the equation valid.
AlexFokin [52]

Answer:

4x³

Step-by-step explanation:

d/dx ln(x⁴ + 7) = 1/(x⁴ + 7) × _?

To obtain the missing expression, let us simplify d/dx ln(x⁴ + 7). This can be obtained as follow:

Let y = ln (x⁴ + 7)

Let u = (x⁴ + 7)

Therefore,

ln(x⁴ + 7) = ln u

Thus,

y = ln u

dy/du = 1/u

Next, we shall determine du/dx. This is illustrated below:

u = (x⁴ + 7)

du/dx = 4x³

Finally, we shall determine dy/dx of ln (x⁴ + 7) as follow:

dy/dx = dy/du × du/dx

dy/du = 1/u

du/dx = 4x³

dy/dx = 1/u × 4x³

But:

u = (x⁴ + 7)

Therefore,

dy/dx = 1/(x⁴ + 7) × 4x³

Thus, the missing expression is 4x³

6 0
3 years ago
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