Answer:
![N=5.36*10^{17}](https://tex.z-dn.net/?f=N%3D5.36%2A10%5E%7B17%7D)
Explanation:
From the question we are told that:
Tensile strength of steel ![\sigma_c=370 MPa.=370*10^6](https://tex.z-dn.net/?f=%5Csigma_c%3D370%20MPa.%3D370%2A10%5E6)
Cross-sectional area ![A= 1m^2](https://tex.z-dn.net/?f=A%3D%201m%5E2)
Generally the equation for Total Force is mathematically given by
![F = \frac{G M m}{r^2}](https://tex.z-dn.net/?f=F%20%3D%20%5Cfrac%7BG%20M%20m%7D%7Br%5E2%7D)
![F=\frac{6.67*10^{-11}*7.35*10^{22}*5.97*10^{24}}{(384*10^3)^2}](https://tex.z-dn.net/?f=F%3D%5Cfrac%7B6.67%2A10%5E%7B-11%7D%2A7.35%2A10%5E%7B22%7D%2A5.97%2A10%5E%7B24%7D%7D%7B%28384%2A10%5E3%29%5E2%7D)
Since this is the force of each cable
![F=\sigma_c NA](https://tex.z-dn.net/?f=F%3D%5Csigma_c%20NA)
![F= 370*10^6*N*1](https://tex.z-dn.net/?f=F%3D%20370%2A10%5E6%2AN%2A1)
Therefore
![370*10^6*N*1=\frac{6.67*10^{-11}*7.35*10^{22}*5.97*10^{24}}{(384*10^3)^2}](https://tex.z-dn.net/?f=370%2A10%5E6%2AN%2A1%3D%5Cfrac%7B6.67%2A10%5E%7B-11%7D%2A7.35%2A10%5E%7B22%7D%2A5.97%2A10%5E%7B24%7D%7D%7B%28384%2A10%5E3%29%5E2%7D)
![N=5.36*10^{17}](https://tex.z-dn.net/?f=N%3D5.36%2A10%5E%7B17%7D)
Julius Robert Mayer discovered the Law of Conservation of Energy.
Answer:
The source of energy that is used to power the movement of contraction in working muscles is adenosine triphosphate (ATP) – the body's biochemical way to store and transport energy. However, ATP is not stored to a great extent in cells. So once muscle contraction starts, the making of more ATP must start quickly.
Explanation: Brainliest?
Answer:
Explanation:
Total momentum of the system before the collision
.5 x 3 - 1.5 x 1.5 = -0.75 kg m/s towards the left
If v be the velocity of the stuck pucks
momentum after the collision = 2 v
Applying conservation of momentum
2 v = - .75
v = - .375 m /s
Let after the collision v be the velocity of .5 kg puck
total momentum after the collision
.5 v + 1.5 x .231 = .5v +.3465
Applying conservation of momentum law
.5 v +.3465 = - .75
v = - 2.193 m/s
2 ) To verify whether the collision is elastic or not , we verify whether the kinetic energy is conserved or not.
Kinetic energy before the collision
= 2.25 + 1.6875
=3.9375 J
kinetic energy after the collision
= .04 + 1.2 =1.24 J
So kinetic energy is not conserved . Hence collision is not elastic.
3 ) Change in the momentum of .5 kg
1.5 - (-1.0965 )
= 2.5965
Average force applied = change in momentum / time
= 2.5965 / 25 x 10⁻³
= 103.86 N
Answer:
Answer:
4 ms
Explanation:
initial velocity, u = 75 m/s
final velocity, v = 0
distance, s = 15 cm = 0.15 m
Let the acceleration is a and the time taken is t.
Use third equation of motion
v² = u² + 2 a s
0 = 75 x 75 - 2 a x 0.15
a = - 18750 m/s^2
Use first equation of motion
v = u + at
0 = 75 - 18750 x t
t = 4 x 10^-3 s
t = 4 ms
thus, the time taken is 4 ms.
Explanation: