Answer:
The average linear velocity (inches/second) of the golf club is 136.01 inches/second
Explanation:
Given;
length of the club, L = 29 inches
rotation angle, θ = 215⁰
time of motion, t = 0.8 s
The angular speed of the club is calculated as follows;
The average linear velocity (inches/second) of the golf club is calculated as;
v = ωr
v = 4.69 rad/s x 29 inches
v = 136.01 inches/second
Therefore, the average linear velocity (inches/second) of the golf club is 136.01 inches/second
The momentum of the object is 8050 kg m/s
Explanation:
The momentum of an object is defined as
where
p is the momentum
m is the mass
v is the velocity of the object
For the object in this problem, we have
m = 500 kg is its mass
v = 58 km/h is its velocity
Converting the velocity into m/s,
Therefore now we can find the momentum of the object:
Learn more about momentum:
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Answer:
(a) 135 kV
(b) The charge chould be moved to infinity
Explanation:
(a)
The potential at a distance of <em>r</em> from a point charge, <em>Q</em>, is given by
where
Difference in potential between the points is
(b)
If this potential difference is increased by a factor of 2, then the new pd = 135 kV × 2 = 270 kV. Let the distance of the new location be <em>x</em>.
The charge chould be moved to infinity