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Harman [31]
3 years ago
15

Acceleration is best defined as the rate of change of __________ of an object. A. position B. force C. speed D. velocity 2. Whic

h of the following describes acceleration? A. s/m B. m/s C. m/s2 D. m2 3. Which of the following is the main difference between speed and velocity? A. Speed has direction and velocity B. Speed is measured over time C. Velocity has both speed and direction D. Speed is constant
Physics
2 answers:
Fittoniya [83]3 years ago
7 0
Velocity!
Hope this helps!
oksian1 [2.3K]3 years ago
3 0
Acceleration is the rate at which an object changes its' velocity. It's measured in m/s^2
D. 
C.
velocity is the rate of change of an objects position. 
C. velocity has speed and direction
(speed does not have direction)
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While a roofer is working on a roof that slants at 37.0 ∘∘ above the horizontal, he accidentally nudges his 92.0 NN toolbox, cau
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Answer:

The speed is   v =8.17 m/s

Explanation:

From the question we are told that

      The angle of slant is  \theta = 37.0^o

       The weight of the toolbox is  W_t = 92.0N

       The mass of the toolbox is m = \frac{92}{9.8} = 9.286kg

       The start point is  d = 4.25m from lower edge of roof

        The kinetic frictional force is  F_f = 22.0N

Generally the net work done on this tool box can be mathematically represented as

      Net \ work done  =  Workdone \ due \ to \ Weight + Workdone \ due \ to \ Friction

The workdone due to weigh is  =    mgsin \theta * d

 The workdone due to friction is  = F_f \ cos\theta  *   d

Substituting this into the equation for net workdone  

                 W_{net} = mgsin\theta  * d + F_f  \ cos \theta *d

      Substituting values

                  W_{net}  =  92 * sin (37)  * 4.25 + 22 cos (37) * 4.25

                          = 309.98 J

 According to work energy theorem

             W_{net} = \Delta Kinetic \ Energy

              W_{net} = \frac{1}{2} m (v - u)^2

From the question we are told that it started from rest so  u = 0 m/s

              W_{net} = \frac{1}{2} * m v^2

Making v the subject

               v = \sqrt{\frac{2 W_{net}}{m} }

Substituting value

              v = \sqrt{\frac{2 * 309.98}{9.286} }

             v =8.17 m/s

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Answer:

FAE= 0.014 N

Explanation:

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Answer:

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