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madam [21]
3 years ago
11

What is a small sacle industry?​

Physics
1 answer:
galina1969 [7]3 years ago
3 0
Small enterprises who manufacture goods or services with the help of relatively smaller machines and a few workers and employees
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What formula oan be used to determine the velocity of an object in free fall?​
belka [17]

Answer:

A

Explanation:

8 0
3 years ago
Read 2 more answers
Jim strikes a 0.058 kg golf ball with a force of 272 N, giving it a velocity of 62.0 m/s. How long was the ball in contact with
Mekhanik [1.2K]

Answer: 0.013 seconds

Explanation:

Given that

Mass of golf ball = 0.058 kg

Force = 272 N

Velocity = 62.0 m/s

Time taken = ?

Recall that force is the rate of change of momentum per unit time

i.e Force = Change in momentum / Time

i.e Force = (Mass x velocity) / Time

272N = (0.058 kg x 62.0 m/s) / Time

272N = 3.6kgm/s / Time

Time = (3.6kgm/s / 272N)

Time = 0.013 seconds

Thus, the ball was in contact with the club for 0.013 seconds

8 0
4 years ago
A ladder is slipping down a vertical wall. If the ladder is 10 ft long and the top of it is slipping at the constant rate of 4 ​
Andrei [34K]

Answer:

Speed will be: 1.33ft/s

Explanation:

If ladder is 10 ft long and bottom is 8 ft from the wall then by Pythagoras theorem we can find the height of the wall where ladder touches. (before it started slipping)

10^2 = 8^2 + x^2

thus x^2 = 100 - 64 = 36

Giving x= 6 ft. If the ladder is falling with a speed of 4ft/s it will take 1.5 seconds to cover the 6ft distance.

This shows that the bottom of ladder will travel from 8ft to 10 ft in 1.5 seconds. Thus covering 2 ft in 1.5 seconds making the speed to be:

v = S / t

v = 2 / 1.5

v = 1.33 ft/s

8 0
4 years ago
Describe how Newton’s third law applies to the box and the table.
Snowcat [4.5K]

Answer:

the box has vertical force on the table

Explanation:

There can be no single isolated force, for every action there must be a force of reaction of ingual magnitude and direction, but in the opposite direction

3 0
4 years ago
Read 2 more answers
A uniform stick has a mass of 4.42 kg and a length of 1.23 m. It is initially lying flat at rest on a frictionless horizontal su
nataly862011 [7]

10.7 rad/s is the final angular velocity of the stick.

Given:

Mass of the stick = 4.42 kg

Length of the stick = 1.23m

Force of impulse (I) = 12.8 N s

The linear velocity of the stick, v=\frac{I}{m}

                                                  v=\frac{12.8 N.s (\frac{1 kg m/s^2}{1 N}) }{4.42 kg}

                                                  v  = 2.89 m/s

Therefore, the final linear velocity of the stick is 2.89 m/s

∴w=\frac{12 Ir}{ml^{2} }

w=\frac{12 ( 12.8 N.s ) ( 46.4 cm)}{(4.42 kg) (1.23 m)^2}

w= \frac{12 (12.8 N.s) (46.4 cm) (\frac{10^-^2 m}{1 cm} )}{(4.42 kg) (1.23m)2}

w=10.7   rad/s

Therefore, 10.7 rad/s is the final angular velocity of the stick.

Learn more about linear velocity here:

brainly.com/question/15154527

#SPJ4

                                                 

5 0
2 years ago
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