Answer: 0.013 seconds
Explanation:
Given that
Mass of golf ball = 0.058 kg
Force = 272 N
Velocity = 62.0 m/s
Time taken = ?
Recall that force is the rate of change of momentum per unit time
i.e Force = Change in momentum / Time
i.e Force = (Mass x velocity) / Time
272N = (0.058 kg x 62.0 m/s) / Time
272N = 3.6kgm/s / Time
Time = (3.6kgm/s / 272N)
Time = 0.013 seconds
Thus, the ball was in contact with the club for 0.013 seconds
Answer:
Speed will be: 1.33ft/s
Explanation:
If ladder is 10 ft long and bottom is 8 ft from the wall then by Pythagoras theorem we can find the height of the wall where ladder touches. (before it started slipping)

thus 
Giving x= 6 ft. If the ladder is falling with a speed of 4ft/s it will take 1.5 seconds to cover the 6ft distance.
This shows that the bottom of ladder will travel from 8ft to 10 ft in 1.5 seconds. Thus covering 2 ft in 1.5 seconds making the speed to be:
v = S / t
v = 2 / 1.5
v = 1.33 ft/s
Answer:
the box has vertical force on the table
Explanation:
There can be no single isolated force, for every action there must be a force of reaction of ingual magnitude and direction, but in the opposite direction
10.7 rad/s is the final angular velocity of the stick.
Given:
Mass of the stick = 4.42 kg
Length of the stick = 1.23m
Force of impulse (I) = 12.8 N s
The linear velocity of the stick, 


Therefore, the final linear velocity of the stick is 2.89 m/s
∴



Therefore, 10.7 rad/s is the final angular velocity of the stick.
Learn more about linear velocity here:
brainly.com/question/15154527
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