Answer:
a. y = 2/5x + 1/5
Step-by-step explanation:
In point-slope form, the equation of a line with slope m through point (h, k) can be written
y = m(x -h) +k
Then a line with slope 2/5 through the point (-3, -1) will have point-slope equation ...
y = (2/5)(x +3) -1
This can be simplified to the desired form:
y = 2/5x +6/5 -1 . . . . . . eliminate parentheses; next, collect terms
y = 2/5x + 1/5
Given:
The graph of a function is given.
To find:
The range of the graph.
Solution:
We know that, the domain is the set of input values and range is the set of output values.
In a graph, domain is represented by the x-axis and range is represented by the y-axis.
From the given graph it is clear that there is an open circle at (-8,-8) and a closed circle at (3,4). It means the function is not defined at (-8,-8) but defined for (3,4).
The graph of the function is defined over the interval . So, the domain is (-8,3].
The values of the function lie in the interval . So, the range is (-8,4].
Therefore, the range of the function are all real values over the interval (-8,4].