Answer:
Where the electric potential is constant, the strength of the electric field is zero.
Explanation:
As a test charge moves in a given direction, the rate of change of the electric potential of the charge gives the potential gradient whose negative value is the same as the value of the electric field. In other words, the negative of the slope or gradient of electric potential (V) in a direction, say x, gives the electric field (Eₓ) in that direction. i.e
Eₓ = - dV / dx ----------(i)
From equation (i) above, if electric potential (V) is constant, then the differential (which is the electric field) gives zero.
<em>Therefore, a constant electric potential means that electric field is zero.</em>
Answer:
Explanation:
Let velocity of helium atom before the collision be v and velocity of oxygen atom be V
Applying the law o conservation of momentum along the line of collision
6.646 x 10⁻²⁷v + 0 = 6.646 x 10⁻²⁷ x 6.636×10⁶ cos 84.7 + 2.656 x 10⁻²⁶ V cos40.4
6.646 x 10⁻²⁷v + 0 = 4.07 x 10⁻²¹ + 2.02 x 10⁻²⁶ V
6.646 x 10⁻⁻²⁷ v = 4.07 x 10⁻²¹ + 2.02 x 10⁻⁻²⁶ V
Applying law of conservation of momentum in a direction perpendicular to original direction of motion
6.646 x 10⁻²⁷ x 6.636×10⁶ sin 84.7 - 2.656 x 10⁻²⁶ V sin40.4 = 0
43.91 x 10⁻²¹ = 1.7214 x 10⁻²⁶V
V = 43.91 / 1.7214 x 10⁵ m /s
= 25.5 x 10⁵ m /s
Putting this value in the earlier equation
6.646 x 10⁻⁶ v = 4.07 x 10⁻²¹ + 2.02 x 10⁻⁵ V
6.646 x 10⁻⁶ v = 4.07 x 10⁻²¹ + 2.02 x10⁻²⁶ x 25.5 x 10⁵
6.646 x 10⁻²⁷ v = 4.07 x 10⁻²¹ + 51.51 x10⁻²¹ = 55.58 x 10⁻²¹
v = 55.58 x 10⁻²¹ / 6.646 x 10⁻²⁷
= 8.36 x 10⁶ m /s
Answer:
2.45 m
Explanation:
We are given that
Height,h=0.75 m
Initial velocity,
We have to find the height above his own starting point Ed rises.
Initial kinetic energy of Ed=Final potential energy of Ed
According to law of conservation of momentum
Initial kinetic energy of adolf=Final potential energy of adolf
Substitute the values
Answer:
0.444atm
Explanation:
Using the combined gas law equation;
P1V1/T1 = P2V2/T2
Where;
P1 = initial pressure (
P2 = final pressure (
V1 = initial volume (L)
V2 = final volume (L)
T1 = initial temperature (K)
T2 = final temperature (K)
According to this question,
P1 = 101.3 kPa = 101.3 × 0.00987 = 0.999atm
P2 = ?
V1 = 80L
V2 = 160L (double of V1)
T1 = 34°C = 34 + 273 = 307K
T2 = 0°C = 0 + 273 = 273K
Using P1V1/T1 = P2V2/T2
0.999 × 80/307 = P2 × 160/273
79.92/307 = 160P2/273
Cross multiply
307 × 160P2 = 79.92 × 273
49120P2 = 21818.16
P2 = 21818.16 ÷ 49120
P2 = 0.444
P2 = 0.444atm