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vodka [1.7K]
3 years ago
7

B is between A and C. AB = 3x, BC = 2x + 7, AC = 42 a) X = b)AB = c)BC=

Mathematics
1 answer:
ryzh [129]3 years ago
5 0

Answer: x=7

               ab=21

               bc=14

Step-by-step explanation:

ab=3x

bc=2x±7

ac=42

3x±2x±7=42

5x±7=42

5x=42-7

5x=35

to get the value of x you divide 35 by 5x

35÷5x=7

so the value of x is 7

ab=3x

x=7

3x=7×3x

7×3=21

x=7

2x=7×2x

2×7=14

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\bold{\huge{\underline{ Solution }}}

<u>Before </u><u>answering </u><u>the </u><u>given </u><u>question</u><u>, </u><u>you </u><u>should </u><u>know </u><u>the </u><u>difference </u><u>between </u><u>polygon </u><u>and </u><u>regular </u><u>polygon</u><u>. </u>

  • Polygon :- It is closed figure constitute of straight line having different measurements and also having varies angles.
  • Regular polygon :- It is also a closed figure constitute of straight lines which having equal measuresment and all the angles of the given polygon are equal .

<u>There </u><u>are </u><u>different </u><u>types </u><u>of </u><u>polygon </u><u>based </u><u>on </u><u>the </u><u>sides </u><u>:</u><u>-</u>

  • A polygon having 3 sided called triangle ,having 4 sides called quadrilateral ,having 5 sides pentagon and so on.

<h3><u>Let's </u><u>Begin </u><u>:</u><u>-</u></h3>

I have thought to make a 4 side polygon that is quadrilateral.

<u>Steps </u><u>of </u><u>construction </u><u>:</u><u>-</u><u> </u>

  • Step - 1 :- Draw a 5 cm line AB horizontally
  • Step - 2 :- Then , From a point B, Draw a Vertical line of 5 cm and named it BC
  • Step - 3 :- Then, From a point C, Draw a horizontal line of 5 cm and named it CD
  • Step - 4 :- Now, join the line AD
  • Step - 5 :- Measure all the angles form by the 4 sides of the quadrilateral.

<u>Result </u><u>:</u><u>-</u><u> </u> All the angles are equal that is 90° each.

<u>Conclusion </u><u>:</u><u>-</u><u> </u> The above figure is square as it is having equal sides and angles.

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<u>Here</u><u>, </u><u> </u>

  • All angles are equal in measure 90°

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\sf{ = 180{\degree} + 90{\degree} + 90{\degree} }

\sf{ = 270{\degree} + 90{\degree} }

\sf{ = 360{\degree} }

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