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Lilit [14]
2 years ago
11

Is y=2x+3 proportional

Mathematics
2 answers:
adell [148]2 years ago
8 0

No because something proportional can't have a y-intercept, the 3 is the y intercept so your statement is not proportional.

Nataly [62]2 years ago
7 0

Answer:

no

Step-by-step explanation:

I calculated

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Each side of a square is increasing at a rate of 5 cm/s. At what rate (in cm2/s) is the area of the square increasing when the a
nikklg [1K]

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knkkl

Step-by-step explanation:

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4 0
2 years ago
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a group 5 friends want to buy a flat screen tv for $ 210. the tax comes to $15. write and solve a multiplication equation to fin
Greeley [361]

Let x be the amount each friend pays .

There are five friends contributing ,so 5x will be the total money collected .

It needs to equal the price plus the tax, 210 + 15 = 225

So the equation becomes,

5x = 210 + 15

5x = 225

dividing right side by 5, we have

x = 225/5 = 45

Answer: So each frien pays $45.

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3 years ago
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The triangles shown are similar. What is the value of x?
Pavlova-9 [17]

Answer:

x = 10

Step-by-step explanation:

The bigger triangle is 2 times larger than the smaller triangle meaning all of the value of the smaller triangle are 2 times smaller than the bigger triangle and the bigger triangle is 2 times larger than the smaller triangle

6 0
2 years ago
Read 2 more answers
A manufacturing company has two retail outlets. It is known that 30% of all potential customers buy
aleksandrvk [35]

Answer:

(a) A y P(A) = 0.4 (b) \bar{B} y P(\bar{B})=0.5 (c) \bar{A}∪\bar{B} y P(\bar{A}∪\bar{B}) = 0.9 (d) \bar{A}∩\bar{B} y P(\bar{A}∩\bar{B})=0.2

Step-by-step explanation:

A was defined as the event that a potential customer, randomly chosen, buys from outlet 1 in the original problem statement. We know that B denotes the event that a randomly chosen customer buys from outlet 2. So

P(A\cap \bar{B}) = 0.3, P(B\cap \bar{A}) = 0.4 and P(A\cap B) = 0.1

(a) P(A) = P(A\cap (B\cup\bar{B})) = P(A\cap B) + P(A\cap \bar{B}) = 0.1 + 0.3 = 0.4

(b)  P(B) = P(B\cap (A\cup\bar{A})) = P(B\cap A) + P(B\cap \bar{A}) = 0.1 + 0.4 = 0.5

P( \bar{B}) = 1-P(B) = 1-0.5 = 0.5

(c) The customer does not buy from outlet 1 is the complement of A, i.e.,  \bar{A}, and the customer does not buy from outlet 2 is the complement of B, i.e.,  \bar{B}, so, the customer does not buy from outlet 1 or does not buy from outlet 2 is  \bar{A}∪ \bar{B} and P(\bar{A}∪ \bar{B}) = P((A\cap B)^{c}) by De Morgan's laws

P((A\cap B)^{c})  = 1-P(A∩B)=1-0.1=0.9

(d) The customer does not buy from outlet 1 is the complement of A, and the customer does not buy from outlet 2 is the complement of B, so we have that the statement in (d) is equivalent to \bar{A}∩\bar{B} and P( \bar{A}∩\bar{B}) = P((AUB)^{c}) by De Morgan's laws, and

P((AUB)^{c}) = 1-P(A∪B)=1-[P(A)+P(B)-P(A∩B)]=1-[0.4+0.5-0.1]=1-0.8=0.2

8 0
2 years ago
Aubrey's parents are signing her up for summer camps. If there are 5 weeklong camps to choose from, in how many orders can they
Tems11 [23]

Answer:

This can be done in a total of 10 ways

Step-by-step explanation:

This is a selection problem.

What we are trying to do is to properly select 3 week long camps from the total 5. we are looking for the number of ways in which we can do this.

Now, since this is a selection problem, the proper mathematical term and approach to use is the COMBINATION

Mathematically, having r items to pick from a total n, the number of ways to do this is nCr ways

which is mathematically equivalent to;

n!/(n-r)!r!

now applying this to the problem at hand, what we have is 5C3

= 5!/(5-3)!3! = 5!/2!3! = (5 *4)/2 = 20/2 = 10 ways

3 0
3 years ago
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