Ion If we add an electron to a stable element we call it a(n)_____ion anion cation

Chemistry

1 answer:

masha68 [24]2 years ago

3 0

The answer is a cation, I may be wrong but cation is plus and anion is subtract

You might be interested in

Compare natural selection to evolution. Be sure to justify your response in two or more complete sentences.

WINSTONCH [101]

Natural selection is the process in which a weaker, or less advantaged animal loses something to a stronger, more advantaged animal. For example, a frog with a broken leg probably will not get to mate while a healthy frog will. Evolution is the process of an animal gradually changing over the generations biologically. An example of this is the theory that humans slowly evolved from monkeys, gradually becoming more and more human like.

7 0

2 years ago

What is the definition of electron orbital?

Vlada [557]

A function describing the location and wave-like behavior of an electron in an atom.

8 0

1 year ago

Read 2 more answers

What is the first step to solving a problem ?

max2010maxim [7]

Asking a question............

5 0

3 years ago

Give a chemical formula for the compound formed when sulfur dioxide reacts with water

zavuch27 [327]

When sulfur dioxide reacts with water , the product is called sulphurous acid, H2SO3. The balanced equation is expressed in the following manner : SO2 + H2O = H2SO3. There is a one mole to one mole ratio between any of the reactants to product, sulphurous acid.

6 0

2 years ago

Solid NaI is slowly added to a solution that is 0.0079 M Cu+ and 0.0087 M Ag+.Which compound will begin to precipitate first?NaI

NeTakaya

Answer :

AgI should precipitate first.

The concentration of $Ag^+$ when CuI just begins to precipitate is, $6.64\times 10^{-7}M$

Percent of $Ag^+$ remains is, 0.0076 %

Explanation :

$K_{sp}$ for CuI is $1\times 10^{-12}$

$K_{sp}$ for AgI is $8.3\times 10^{-17}$

As we know that these two salts would both dissociate in the same way. So, we can say that as the Ksp value of AgI has a smaller than CuI then AgI should precipitate first.

Now we have to calculate the concentration of iodide ion.

The solubility equilibrium reaction will be:

$CuI\rightleftharpoons Cu^++I^-$