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JulsSmile [24]
3 years ago
5

Ion If we add an electron to a stable element we call it a(n)_____ion anion cation

Chemistry
1 answer:
masha68 [24]3 years ago
3 0
The answer is a cation, I may be wrong but cation is plus and anion is subtract
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How many grams are in 4.23E44 particles of PbO2
ASHA 777 [7]

1.679 × 10²³ g of PbO₂ is present in 4.23×10⁴⁴ particles of PbO₂.

<u>Explanation:</u>

First the number of particles is converted into moles by dividing it by the Avogadro's number and then moles multiplied by the molar mass, we will get the mass of PbO₂ in grams.

4.23×10⁴⁴/ 6.022×10²³ = 7.02×10²⁰ moles

Now we have to multiply this by the molar mass of PbO₂, that is 239.2 g/mol, we will get the mass in grams.

7.02×10²⁰ moles × 239.2 g/mol = 1.679 × 10²³ g of PbO₂

3 0
3 years ago
How many oxygen atoms are in the Perth products of the balanced reaction below
sp2606 [1]

The answer you're looking for is 8

5 0
4 years ago
A certain substance X condenses at a temperature of 123.3 degree C . But if a 650. g sample of X is prepared with 24.6 g of urea
Pavel [41]

Answer:

<u>The molal boiling point elevation constant is 1.59 ≈  1.6</u> Kkgmol^{-1}

Explanation:

To solve this question , we will make use of the equation ,

ΔT_{b} = i*K_{b} *m

<em>where , </em>

  • <em>ΔT_{b} is the change in boiling point of the substance X ( °C or K)</em>
  • <em>i is the Vant Hoff Factor which = 1 in this case ( no unit )</em>
  • <em>K_{b} is the mola boiling point elevation constant of X ( Kkgmol^{-1})</em>
  • <em>m is the molality of the solution which has (NH_{2})_{2} CO as the solute and  X as the solution (molkg^{-1})</em>

  1. ΔT_{b} = 124.3 -123.3 = 1 °C or K;
  2. i=1;
  3. m= \frac{moles of solute}{weight of solvent(kg)}molkg^{-1}

           ∴ m = \frac{\frac{24.6}{60} }{\frac{650}{1000} }

  • <em>as the weight of (NH_{2})_{2} CO is 60g and thus number of moles = \frac{24.6}{60}</em>
  • <em>and the weight of solvent in kg is \frac{650}{1000}</em>

    4. K_{b} ⇒ ?

∴

1=1*K_{b} *\frac{\frac{24.6}{60} }{\frac{650}{1000} }

⇒ K_{b} = 1.59 ≈ 1.6 Kkgmol^{-1}

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It is a solution, because it's the alloy of tin and copper 
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