To find solubility, we need calculate how much potassium sulfate will be dissolved at 100 g of water.
12 g potassium sulfate ------ 75 g water
x g potassium sulfate --------100 g water
x=12*100/75 = 16g
So, solubility of potassium sulfate at 60⁰ C is 16 g potassium sulfate per 100 g of water.
Answer:
4.12 mol
Explanation:
Given data:
Moles of LiOH required = ?
Volume of solution = 4.2 L
Molarity of solution = 0.98 M
Solution:
Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.
Formula:
Molarity = number of moles of solute / L of solution
we will calculate the moles from above given formula.
0.98 M = number of moles / 4.2 L
0.98 M × 4.2 L = number of moles
Number of moles = 0.98 M × 4.2 L
Number of moles = 4.12 mol (M = mol/L)
Answer:
P = 83.16 Watt
Explanation:
Given data:
Mass of box = 2 Kg
velocity of box = 29.7 m/s
Time = 21 sec
Power = ?
Solution:
Formula:
Power = work done/time
Now we will calculate the work done.
W = force × distance ...... (1)
d = speed /time
d = 29.7 m/s× 21 s
d = 623.7 m
Force:
acceleration = 29.7 m/s / 21 s
a = 1.4 m/s²
Force = m×a
Force = 2 kg×1.4 m/s²
Force = 2.8 N
Now we will put the values in equation 1.
W = F × d
W = 2.8 N ×623.7 m
W = 1746.36 Nm
Now for power:
P = W / time
P = 1746 Nm / 21 s
P = 83.16 Watt
