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sasho [114]
3 years ago
9

Explain one of the theories on how post-it notes work

Chemistry
1 answer:
alexgriva [62]3 years ago
5 0
The glue molecules stick to the surface molecules like millions of microscopic magnets.
Hope it helps
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What does converse mean
Xelga [282]

Answer:

engage in conversation.

Explanation:

8 0
3 years ago
Gizmo Student exploration feel the heat if a solute has really strong bonds between its particles , would you expect it to form
Troyanec [42]

Answer:

The temperature of the solute/solvent without any external effect would decrease.

Explanation:

As the bonding between the solute particles is really strong, therefore a large amount of energy is required to overcome these forces. So that the new bonding between the solute and solvent is created.

In order to achieve this, there will be a lot of energy required and that is through the heating process. So the solution will require energy so the solute will dissolve fully either by provision of external force i.e stirring or by heating.

4 0
3 years ago
What sedimentary rock formed from sand deposits
miv72 [106K]

Answer: sandstone

Explanation:

7 0
2 years ago
Consider the following reaction at equilibrium. 2CO2 (g) 2CO (g) + O2 (g) H° = -514 kJ Le Châtelier's principle predicts that th
tiny-mole [99]

Answer:

C. at low temperature and low pressure.

Explanation:

  • <em>Le Châtelier's principle </em><em>states that when there is an dynamic equilibrium, and this equilibrium is disturbed by an external factor, the equilibrium will be shifted in the direction that can cancel the effect of the external factor to reattain the equilibrium.</em>

<em />

  • For the reaction:

<em>2CO₂(g) ⇄ 2CO(g) + O₂(g), ΔH = -514 kJ.</em>

<em></em>

<em><u>Effect of pressure:</u></em>

  • When there is an increase in pressure, the equilibrium will shift towards the side with fewer moles of gas of the reaction. And when there is a decrease in pressure, the equilibrium will shift towards the side with more moles of gas of the reaction.
  • The reactants side (left) has 2.0 moles of gases and the products side (right) has 3.0 moles of gases.

<em>So, decreasing the pressure will shift the reaction to the side with higher no. of moles of gas (right side, products), </em><em>so the equilibrium partial pressure of CO (g) can be maximized at low pressure.</em>

<em></em>

<u><em>Effect of temperature:</em></u>

  • The reaction is exothermic because the sign of ΔH is (negative).
  • So, we can write the reaction as:

<em>2CO₂(g) ⇄ 2CO(g) + O₂(g) + heat.</em>

  • Decreasing the temperature will decrease the concentration of the products side, so the reaction will be shifted to the right side to suppress the decrease in the temperature, <em>so the equilibrium partial pressure of CO (g) can be maximized at low temperature.</em>

<em></em>

  • So, the right choice is:

<em>C. at low temperature and low pressure.</em>

<em></em>

7 0
3 years ago
What is the temperature (in K) of 16.45 moles of methane gas in a 4.95 L container at 4.68 atm?
AlexFokin [52]
Using the ideal gas law: PV=nRT
      P is pressure; V is volume; n is the amount in moles; R=0.082; T is temperature in K.

(4.68)*(4.95)=(16.45)*(0.0821)*T
Solve for T. 
T=17.15
4 0
3 years ago
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