Explain one of the theories on how post-it notes work
1 answer:
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Explanation: An element is represented in the form of where,
X = Symbol of the element
A = Atomic Mass of the element X
Z = Atomic Number of element X
Hence, For the element Justwondoricium,
Symbol = Jw
Atomic number = 120
Atomic Mass = 224
Now, Atomic number = Number of electrons = Number of Protons
Number of electrons = 120
Number of Protons = 120
and Atomic Mass = Number of neutrons + Number of protons
Number of neutrons can be calculated as we know atomic mass and number of neutrons, Putting the numbers we get
Number of neutrons = 224 - 120 = 104
The nearest noble gas to the element having atomic number 120 is Oganesson (Og), which has an atomic number of 118, so the next two electrons will be filled in the 8s orbital.
Electronic Configuration of Jw is
This electronic configuration lets us know about the location of the element in periodic table.
As the electron is entering the 8th shell, it belongs to the 8th period and as the last electron enters the s-orbital, it belongs to the S-block of the periodic table.
When the s-electrons are 1, it belongs to Group 1.
When the s-electrons are 2, it belongs to Group 2.
As this element has 2 s-electrons, it belongs to the Group 2.
Answer:
The mass of Na₂O that can be produced by the chemical reaction of 4.0 grams of sodium with excess oxygen in the reaction is 5.39 grams.
Explanation:
You know the balanced reaction:
4 NA + O₂ ⟶ 2 Na₂O
By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction) react and are produced:
- Na: 4 moles
- O₂: 1 mole
- Na₂O: 2 moles
Being:
- Na: 23 g/ole
- O: 16 g/mole
the molar mass of the compounds participating in the reaction is:
- Na: 23 g/mole
- O₂: 2*16 g/mole= 32 g/mole
- Na₂O: 2*23 g/mole +16 g/mole= 62 g/mole
Then by stoichiometry of the reaction they react and are produced:
- Na: 4 moles* 23 g/mole= 92 g
- O₂: 1 mole*32 g/mole= 32 g
- Na₂O: 2 moles* 62 g/mole= 124 g
Then you can apply the following rule of three: if 92 grams of Na produce 124 grams of Na₂O, 4 grams of Na, how much mass of Na₂O does it produce?
mass of Na₂O=5.39 g
<em><u>The mass of Na₂O that can be produced by the chemical reaction of 4.0 grams of sodium with excess oxygen in the reaction is 5.39 grams.</u></em>