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3 years ago

What would barium do to obtain a noble gas structure? gain 2 electrons lose 2 electrons gain 6 electrons lose 6 electrons

Chemistry

1 answer:

Tema [17]3 years ago

4 0

Answer:

Lose two electrons.

Explanation:

Barium is present in group 2.

It is alkaline earth metal.

Its atomic number is 56.

Its electronic configuration is Ba₅₆ = [Xe] 6s².

In order to attain the noble gas electronic configuration it must loses its two valance electrons.

When barium loses it two electron its electronic configuration will equal to the Xenon.

The atomic number of xenon is 54 so barium must loses two electrons to becomes equal to the xenon.

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Calculate the density of the items below. (D = M/V)<br> 1) M = 15g V = 5.0ml *

grin007 [14]

Answer:

<h3>The answer is 3.0 g/mL</h3>

Explanation:

The density of a substance can be found by using the formula

$density = \frac{mass}{volume} \\$

From the question

mass = 15 g

volume = 5 mL

We have

$density = \frac{15}{5} \\$

We have the final answer as

Hope this helps you

5 0

3 years ago

Which elements have the most similar chemical properties?

bixtya [17]

Answer:

a. Be and Mg

Explanation:

Be (beryllium) and Mg (magnesium) are both found in the alkaline earth metals family (group 2) on the periodic table. Elements in the same family or group have similar properties,

Ca and Br are in groups 2 and 17

Cl and Ar are in groups 17 and 18

Na and P are in groups 1 and 15

4 0

4 years ago

Read 2 more answers

Its common allotropes are red and white

astraxan [27]

The most common allotropes are:-
White phosphorus
Red phosphorus
The red one is an intermediate phase between white and violent phosphorus.

7 0

3 years ago

The monomer of poly(vinyl chloride) has the formula C2H3Cl. If there are 1,565 repeat units in a single chain of the polymer, wh

monitta

Answer:

$\large \boxed{9.780 \times 10^{4}\text{ u}}$

Explanation:

The molecular mass of a monomer unit is:

C₂H₃Cl = 2×12.01 + 3×1.008 + 35.45 = 24.02 + 3.024 + 35.45 = 62.494 u

For 1565 units,

$\text{Molecular mass} = \text{1565 units} \times \dfrac{\text{62.494 u}}{\text{1 unit }} = \mathbf{9.780 \times 10^{4}}\textbf{ u}\\\\\text{The molecular mass of the chain is $\large \boxed{\mathbf{9.780 \times 10^{4}}\textbf{ u}}$}$

8 0

3 years ago

Propane gas, C3H8, is sometimes used as a fuel. In order to measure its energy output as a fuel a 1.860 g sample was combined wi

lisov135 [29]

Answer:

The heat of the reaction is 105.308 kJ/mol.

Explanation:

Let the heat released during reaction be q.

Heat gained by water: Q

Mass of water ,m= 1kg = 1000 g

Heat capacity of water ,c= 4.184 J/g°C

Change in temperature = ΔT = 26.061°C - 25.000°C=1.061 °C

Q=mcΔT

Heat gained by bomb calorimeter =Q'

Heat capacity of bomb calorimeter ,C= 4.643 J/g°C

Change in temperature = ΔT'= ΔT= 26.061°C - 25.000°C=1.061 °C

Q'=CΔT'=CΔT

Total heat released during reaction is equal to total heat gained by water and bomb calorimeter.

q= -(Q+Q')

q = -mcΔT - CΔT=-ΔT(mc+C)

$q=-1.061^oC(1000 g\times 4.184J/g^oC+4.643 J/^oC )=-4,444.15J=-4.444 kJ$

Moles of propane = $\frac{1.860 g}{44 g/mol}=0.0422 mol$

0.0422 moles of propane on reaction with oxygen releases 4.444 kJ of heat.

The heat of the reaction will be:

$\frac{4.444 kJ}{0.0422 mol}=105.308 kJ/mol$

3 0

3 years ago