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3 years ago

What would barium do to obtain a noble gas structure? gain 2 electrons lose 2 electrons gain 6 electrons lose 6 electrons

Chemistry

1 answer:

Tema [17]3 years ago

4 0

Answer:

Lose two electrons.

Explanation:

Barium is present in group 2.

It is alkaline earth metal.

Its atomic number is 56.

Its electronic configuration is Ba₅₆ = [Xe] 6s².

In order to attain the noble gas electronic configuration it must loses its two valance electrons.

When barium loses it two electron its electronic configuration will equal to the Xenon.

The atomic number of xenon is 54 so barium must loses two electrons to becomes equal to the xenon.

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Answer is: Louis Pasteur (1822-1895) disproved spontaneous generation. He boiled liquid with proteins and other nutrients in S-neck flasks and regular flask to kill all microorganism present. In regular flask liquid showed changes when exposed to air and in S-neck flack there was no change (microorganism can not getting in the flask because the S- neck). When he removed S-neck, liquid changed because microorganisms came in liquid.
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3 years ago

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Please help :)<br> I don’t know what to do

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Answer:

1. MgCl2 + Zn -> Mg + ZnCl2

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4. I2 + KF -> it's not going to react

5. Zn + H2SO4 -> ZnSO4 + H2

6.2KBr + Cl2 -> 2KCl + Br2

7. AgNO3 + Na -> NaNO3 + Ag

8. 2NaCl + F2 -> 2NaF + Cl2

9. AgNO3 + Mg(NO3)2 + Ag

10. Ni + H2SO4 -> NiSO4 + H2

11. Al + K2SO4

12. FeCl3 + 3Mn-> 3MnCl + Fe

13. 2Na + 2H2O -> 2NaOH + H2

14. 2K + MgBr2 -> 2KBr + Mg

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3 years ago

The absolute temperature of a gas is increased four times while maintaining a constant volume. What happens to the pressure of

lianna [129]

Answer:

DECREASE BY A FACTOR OF FOUR

Explanation:

Using pressure equation:

P 1 / T1 = P2 /T2 (at constant volume)

P1 = P

T1 =T

P2 = ?

T2 = 4 T

So therefore;

P2 = P1T1/ T2

P2 = P T/ 4 T

P2 = 1/4 P

The pressure is decreased by a factor of four, the new pressure is a quarter of the formal pressure of the gas.

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3 years ago

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Answer:

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3 years ago

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Calculate the concentration of OH in a solution that contains 3.9 10-4 M H30 at 25°C. Identify the solution as acidic, basic or

Norma-Jean [14]

Answer:

Option A) 2.6 × 10⁻¹¹ M, acidic.

Explanation:

The ion-product constant of water $K_{\rm w}$ gives a relationship between $\rm [H_3O^{+}]$ and $\rm [OH^{-}]$ :

$K_{\rm w} = \rm [H_3O^{+}]\cdot [OH^{-}]$ .

The exact value of $K_{\rm w}$ depends on the temperature. Under $\rm 25^{\circ}C$ , $K_{\rm w} \approx 1^{-14}$ .

The question states that $\rm [H_3O^{+}] = 3.9\times 10^{-4}\; M$ . As a result,

$\begin{aligned} {\rm [OH^{-}]} &= \frac{K_{\rm w}}{[{\rm H_3O^{+}}]}\\ &\approx\frac{1^{-14}}{3.9\times 10^{-4}} && \rm {\leftarrow Only~under~25^{\circ}C.}\atop{}\\&\approx \rm 2.6\times 10^{-11}\; M\end{aligned}$ .

A solution is acidic if $\rm [H_3O^{+}] > [OH^{-}]$ .
A solution is neutral if $\rm [H_3O^{+}] = [OH^{-}]$ .
A solution is acidic if $\rm [H_3O^{+}] < [OH^{-}]$ .

$\rm [H_3O^{+}] > [OH^{-}]$ for this solution. As a result, this solution is acidic.

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3 years ago