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3 years ago

What would barium do to obtain a noble gas structure? gain 2 electrons lose 2 electrons gain 6 electrons lose 6 electrons

Chemistry

1 answer:

Tema [17]3 years ago

4 0

Answer:

Lose two electrons.

Explanation:

Barium is present in group 2.

It is alkaline earth metal.

Its atomic number is 56.

Its electronic configuration is Ba₅₆ = [Xe] 6s².

In order to attain the noble gas electronic configuration it must loses its two valance electrons.

When barium loses it two electron its electronic configuration will equal to the Xenon.

The atomic number of xenon is 54 so barium must loses two electrons to becomes equal to the xenon.

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Reduction half reaction: $Cl_2+2e^-\rightarrow 2Cl(g);E^o_{Cl_2/2Cl^-}=1.36V$

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$\Delta G^o=-nFE^o_{cell}$

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n = number of electrons transferred = 2

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Putting values in above equation, we get:

$\Delta G^o=-2\times 96500\times 0.406=-78358J=-7.84\times 10^4J$

Hence, the $\Delta G^o$ for the given reaction is $-7.84\times 10^4J$

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