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3 years ago

13

Bicycles are often on sale in September. The regular price of one bicycle is $223.95. With a 25% discount, what is the sale pric

e of the bicycle? Round to the nearest cent.

2 answers:

VARVARA [1.3K]3 years ago

5 0

Answer:

Step-by-step explanation:

Bicycles are often on sale in September. The regular price of one bicycle is $93.95. With a 15% discount, what is the sale price of the bicycle? Round to the nearest cent.

Bezzdna [24]3 years ago

3 0

In order to find the discount price we would need to find 25% of $223.95.

Step 1: $.25 * 223.95$ . Which is 55.9875 ( 25% of 223.95)

Step 2: Do $223.95 - 55.9875$ , which is your answer 167.9625. If you round it to the nearest cent, it would be $167.96.

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4.. Please help. Is DE←→ perpendicular to FG←→? Why or why not?

olya-2409 [2.1K]

Given:

DE contains the points D(1, -2) and E(3, 4).

FG contains the points F(-1, 2) and G(4, 0).

To find:

Is DE perpendicular to FG.

Solution:

Slope of DE:

$$m=\frac{y_2-y_1}{x_2-x_1}$

Here $x_1=1, y_1=-2, x_2=3, y_2=4$

$$m=\frac{4-(-2)}{3-1}$

$$m=\frac{6}{2}$

m = 3

Slope of FG:

$$m=\frac{y_2-y_1}{x_2-x_1}$

Here $x_1=-1, y_1=2, x_2=4, y_2=0$

$$m=\frac{0-2}{4-(-1)}$

$$m=\frac{-2}{4+1}$

$$m=\frac{-2}{5}$

<em>Two lines are perpendicular if product their slopes are -1.</em>

Slope of DE × Slope of FG

$$=3\times \frac{-2}{5}$

$$= \frac{-6}{5}$

≠ -1

The solution is no, because the product of the slopes is not -1.

3 0

3 years ago

Read 2 more answers

Work out the size of x

topjm [15]

Answer:

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So you do the reverse

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Step-by-step explanation:

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3 years ago

Halla la medida del lado de un cuadrado cuya diagonal es de 14 cm

8_murik_8 [283]

Answer:

The length side of the square is $7\sqrt{2}\ cm$

Step-by-step explanation:

<u><em>The question in English is</em></u>

Find the measure of the side of a square whose diagonal is 14 cmd

Let

d ----> the diagonal of a square in cm

b ---> the length side of a square in cm

we know that

Applying the Pythagorean Theorem

see the attached figure to better understand the problem

$d^2=b^2+b^2$

$d^2=2b^2$

we have

$d=14\ cm$

substitute the given value

$14^2=2b^2$

solve for b

$196=2b^2$

$98=b^2$

take square root both sides

$b=\sqrt{98}\ cm$

simplify

$b=7\sqrt{2}\ cm$

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