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3 years ago

Meg's Bakery sells the following items.

Mathematics

1 answer:

Readme [11.4K]3 years ago

5 0

Answer:

it is $2.50 multiplied by 4

Step-by-step explanation:

this is because for every 1 cinnamon roll it is $2.50 and if you multiply that by 4 you get $10, or how much it costs for 1 roll

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How many soulutions does the system of equations have x-3y=15. and 3x-9y=45

Irina-Kira [14]

Answer:

<h2>Infinitely many solutions</h2>

Step-by-step explanation:

$\left\{\begin{array}{ccc}x-3y=15\\3x-9y=45\end{array}\right\\\\\text{Divide both sides of the second equation by 3}\\\\\dfrac{3x}{3}-\dfrac{9y}{3}=\dfrac{45}{3}\\\\x-3y=15\\\\\text{We received the same equation as the first.}\\\\\bold{CONCLUSION}\\\\\text{The system of equations has infinitely many solutions.}$

$\left\{\begin{array}{ccc}a_1x+b_1y=c_1\\a_2x+b_2x=c_2\end{array}\right\\\\\text{If}\ a_1=a_2,\ b_2=b_2,\ c_1=c_2,\ \text{then the system of equations}\\\text{ has infinitely many solutions}\\\\\text{If}\ a_1=a_2,\ b_1=b_2,\ c_1\neq c_2,\ \text{then the system of equations}\\\text{has no solutions}\\\\\text{Other the system of equations has one solution.}$

5 0

3 years ago

In the diagram below of triangle EFG, H is a midpoint of EF and J is a midpoint

cricket20 [7]

try it on

https://www.wolframalpha.com it will helpp you for the math problem :)

5 0

3 years ago

Identify the distance between points (−1,7,10) and (6,−3,2), and identify the midpoint of the segment for which these are the en

svetlana [45]

Answer:

d ≈ 14.6 units; M (2.5, 2, 6)

Step-by-step explanation:

Using the distance formula for 3-D dimensions, you get the √(213) which equals 14.6

Then, using the midpoint formula for 3-D dimensions, you find the coordinates 2.5 for x, 2 for y, and 6 for z.

3 0

2 years ago

Centerville is the headquarters of Greedy Cablevision Inc. The cable company is about to expand service to two nearby towns, Spr

NeX [460]

Answer:

20.2057 Units.

Step-by-step explanation:

First, we determine the length of the cable.

Distance between Centerville (8,0) and point (x,0) is given as:

$\sqrt{(8-x)}^2=8-x$

Distance between point (x,0) and Springfield(0,7) is:

$\sqrt{(7-0)^2+(0-x)^{2}}=\sqrt{(7)^2+(x)^{2}}$

Distance between point (x,0) and Shelvyfield(0,-7) is:

$\sqrt{(-7-0)^2+(0-x)^{2}}=\sqrt{(7)^2+(x)^{2}}$

Therefore the Length of the Cable L(x)

$L(x)=(8-x)+2\sqrt{(7)^2+(x)^{2}}$

To find the critical point, we set the derivative of L(x)=0

$L^{'}(x)=-1+\frac{2x}{\sqrt{\left( 49 - x^{2}\right) }}$

$\frac{-\sqrt{\left( 49 - x^{2}\right)}+2x}{\sqrt{\left( 49 - x^{2}\right)}}=0\\-\sqrt{\left( 49 - x^{2}\right)}+2x=0\\\sqrt{\left( 49 - x^{2}\right)}=2x\\(\sqrt{\left( 49 - x^{2}\right)})^2=(2x)^2\\49 - x^{2}=4x^2\\49=5x^2\\x^2=\frac{49}{5}\\x= 3.1305$

To verify that L(x) has a minimum at this critical number we compute the second derivative L″(x) and find its value at the critical number.

$L^{''}(x)=\frac{\left( 98\right) \,\sqrt{\left( 49 - x^{2}\right) }}{{\left( 7 - x\right) }^{2}\,{\left( 7+x\right) }^{2}}\\At \:x=3.1305, L^{''}=0.3993$

Since $L^{''}(x)$ is positive, the minimum point of L(x) exists.

Next, we find the minimum length by substituting z=3.1305 into L(x)

$L(3.1305)=(8-3.1305)+2\sqrt{(7)^2+(3.1305)^{2}}$

Minimum Length, L=20.2057

The minimum length of the cable is 20.2057 Units.

6 0

3 years ago

Two sides of a triangle have lengths of 18 and 29 units. if the third side has an integer length, what is the positive differenc

Andru [333]

Triangular inequality: Length of third side must be less than the sum of the lengths of the other 2 sides.
x < 18 + 29
x < 47

so Maximum length of third side is 46 units.

Also 29 < 18 + x
x > 11 so minimum length = 12

Difference = 46-11 = 35

3 0

3 years ago