Answer:
A Brønsted-Lowry acid.
A Brønsted-Lowry base.
Ammonia is an acceptor of proton.
Explanation:
A Brønsted-Lowry acid is any atom that can donate a proton (H +) to another atom or molecule whereas Brønsted-Lowry base is any species that can accept a proton from another atom or molecule or in other words, a Brønsted-Lowry acid is a proton donor, while on the other hand, a Brønsted-Lowry base is a proton acceptor. The ammonia molecule accepts the hydrogen ion is considered as the Brønsted-Lowry base.
Answer: 4.99×10²³ photons
Explanation: The energy of a photon is given as
E= hf
h= Planck constant = 6.626×10^-34Js
f= frequency = c/x
C= speed of light = 3×10^8 m/s
x= wavelength= 525nm= 525×10^-9
E= hc/x
E= 6.626×10^-34 × 3×10^8 m/s /( 525×10^-9)
E= 3.79×10^−19 J/ Photon
E= 3.79×10^−22KJ/Photon
189KJ/3.79×10^−22KJ/photon=
4.99×10²³photons.
Therefore the number of photons is
4.99×10²³photons.
Answer:
Ground state electronic configuration of oxygen atom is as follows - is 1s2 2s2 2p2x 2p1y 2p1z 1s2 2s2 2px2 2py1 2pz1
Ground state electronic configuration of hydrogen atom is 1s1 1s1
Explanation:
As per the Valence Bond Theory (VBT),
Ground state electronic configuration of oxygen atom is as follows - is 1s2 2s2 2p2x 2p1y 2p1z 1s2 2s2 2px2 2py1 2pz1
Ground state electronic configuration of hydrogen atom is 1s1 1s1
Considering the electronic configuration, H-O-H bond angle would be at 90 degrees as 2py2py and 2pz2pz are oriented 90° with respect to each other. But if the oxygen atomic orbitals is used directly then bond angle for water is 104.45° as per the VSEPR theory which states that 2s2s spherical orbit in oxygen can adjust the bond angle by creating new hybrid orbitals
The reactants are those which react with each other to give the desired result.
The product is this result of reactants.
Thus, here option "D." Is correct.