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mel-nik [20]
3 years ago
7

Why are only some minerals found as native minerals? For example, iron and aluminum are almost never found as native elements in

nature.
Chemistry
1 answer:
Keith_Richards [23]3 years ago
7 0

Answer: Metals found as native minerals in nature are not highly reactive

Explanation:

Native minerals refers to minerals that are found in nature in their pure metallic form such as gold. Iron and aluminum are highly reactive metals. Highly reactive metals are far up in the activity series of metals, they have a great tendency towards oxidation. On the other hand, noble metals have less tendency towards oxidation and are found close to the bottom of the activity series for example, gold.

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If a pork roast must absorb kJ to fully cook, and if only 10% of the heat produced by the barbecue is actually absorbed by the r
kolezko [41]

Answer:

1,033.56 grams of carbon dioxide was emitted into the atmosphere.

Explanation:

C_3H_8(g)+5O_2(g)\rightarrow 3CO_2(g)+4H_2O(g),\Delta H_{rxn}=-2044 kJ/mol (assuming)

Energy absorbed by pork,E = 1.6\times 10^3 kJ (assuming)

Total energy produced by barbecue = Q

Percentage of energy absorbed by pork = 10%

10\%=\frac{E}{Q}\times 100

Q=\frac{E}{10}\times 100=\frac{1.6\times 10^3 kJ}{10}\times 100=1.6\times 10^4 kJ

Since, it is a energy produced in order to indicate the direction of heat produced we will use negative sign.

Q = -1.6\times 10^4 kJ

Moles of propane burnt to produce Q energy =n

n\times \Delta H_{rxn}=Q

n=\frac{Q}{\Delta H_{rxn}}=\frac{-1.6\times 10^4 kJ}{-2044 kJ/mol}=7.83 mol

According to reaction , 1 mol of propane gives 3 moles of carbon dioxide. then 7.83 moles of will give:

\frac{1}{3}\times 7.83 mol=23.49 mol carbon dioxide gas.

Mass of 23.49 moles of carbon dioxide gas:

23.49 mol × 44 g/mol =1,033.56 g

1,033.56 grams of carbon dioxide was emitted into the atmosphere.

8 0
3 years ago
Which of the following is a combustion reaction?
Rina8888 [55]
The answer is b it is a combustion reaction
7 0
4 years ago
How many milliliters of 0.100 m naoh are required to neutralize 9.00 ml of 0.0500 m hcl?
BabaBlast [244]
V  ( NaOH ) = mL ?

M ( NaOH ) = 0.100 M

V ( HCl ) = 9.00 mL / 1000 => 0.009 L

M ( HCl ) = 0.0500 M

number of moles HCl:

n = M x V

n = 0.009 x 0.0500 => 0.00045 moles HCl

mole ratio:

<span>HCl + NaOH = NaCl + H2O
</span>
 1 mole HCl ---------------- 1 mole NaOH
 0.00045 moles HCl ----- ??

0.00045 x 1 / 1 => 0.00045 moles of NaOH

M = n / V

0.100 = 0.00045 / V

V = 0.00045 / 0.100

V = 0.0045 L

1 L ------------ 1000 mL
0.0045 L ----- ??

0.0045 x 1000 / 1 => 4.5 mL of NaOH



6 0
4 years ago
DDT:
Assoli18 [71]

Answer:

d. it does all of that and even harms humans to some extent

let me know if its right

8 0
3 years ago
The pHof a buffer solution containing 0.10 Macetic acid and 0.10 M
zysi [14]

<span>Chemical reaction: CH</span>₃COO⁻(aq) + H⁺(aq) ⇄ CH₃COOH(aq).

H⁺ is from HNO₃: HNO₃ → H⁺ + NO₃⁻.

<span>A buffer can be defined as a substance that prevents the pH of a solution from changing by either releasing or absorbing H</span>⁺ in a solution.

Buffer is a solution that can resist pH change upon the addition of an acidic or basic components and it is able to neutralize small amounts of added acid or base, pH of the solution is relatively stable.

8 0
3 years ago
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