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mel-nik [20]
3 years ago
7

Why are only some minerals found as native minerals? For example, iron and aluminum are almost never found as native elements in

nature.
Chemistry
1 answer:
Keith_Richards [23]3 years ago
7 0

Answer: Metals found as native minerals in nature are not highly reactive

Explanation:

Native minerals refers to minerals that are found in nature in their pure metallic form such as gold. Iron and aluminum are highly reactive metals. Highly reactive metals are far up in the activity series of metals, they have a great tendency towards oxidation. On the other hand, noble metals have less tendency towards oxidation and are found close to the bottom of the activity series for example, gold.

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An aqueous CsCl solution is 8.00 wt% CsCl and has a density of 1.0643 g/mL at 20°C. What is the boiling point of this solution?
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<u>Answer:</u> The boiling point of solution is 100.53

<u>Explanation:</u>

We are given:

8.00 wt % of CsCl

This means that 8.00 grams of CsCl is present in 100 grams of solution

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The equation used to calculate elevation in boiling point follows:

\Delta T_b=\text{Boiling point of solution}-\text{Boiling point of pure solution}

To calculate the elevation in boiling point, we use the equation:

\Delta T_b=iK_bm

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\text{Boiling point of solution}-\text{Boiling point of pure solution}=i\times K_b\times \frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}

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Boiling point of pure solution = 100°C

i = Vant hoff factor = 2 (For CsCl)

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m_{solute} = Given mass of solute (CsCl) = 8.00 g

M_{solute} = Molar mass of solute (CsCl) = 168.4  g/mol

W_{solvent} = Mass of solvent (water) = 92 g

Putting values in above equation, we get:

\text{Boiling point of solution}-100=2\times 0.51^oC/m\times \frac{8.00\times 1000}{168.4g/mol\times 92}\\\\\text{Boiling point of solution}=100.53^oC

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