I found the value for number 2 and it took some time to like calculate but here it is
$15,250
1.)$14,106.25
2.)$13,048.2812
3.)$12,069.6601
4.)$11,164.4356
5.)$10,327.1029
6.)$9,552.57018
7.)$8,836.12742
8.)$8,173.42
The numbers are the years but the value of the car would be number 8
Answer:
$1.25 to park a car and $3.50 to park a truck
Step-by-step explanation:
Set up a system where c is the number of cars parked and t is the number of trucks:
3c + 2t = 10.75
7c + t = 12.25
Solve by elimination by multiplying the bottom equation by -2 to eliminate t:
3c + 2t = 10.75
-14c - 2t = -24.5
Add them together and solve for c:
-11c = -13.75
c = 1.25
Then, plug in 1.25 as c in the equation to solve for t:
3c + 2t = 10.75
3(1.25) + 2t = 10.75
3.75 + 2t = 10.75
2t = 7
t = 3.5
So, it costs $1.25 to park a car and it costs $3.50 to park a truck
The U in the upper right corner stands for the universal set.
As universal set defined the set containing all objects or elements and of which all other sets are subsets. So, the answer is B.
4/16 or 1/4 because 1 + 1 + 2 is 4 & 3 + 5 + 8 is 16 so the fraction will be 4/16 but u can also divide both by 4’s which is 1/4.
Me. Hamel is the answer I believe. 9x4=36 4 sides each one is 9. :)
