All categories

3 years ago

What's the ph of 0.0000067 m hcl solution

Chemistry

1 answer:

statuscvo [17]3 years ago

5 0

Answer:

$pH = - log[H {}^{ + } ] \\ = - log(0.0000067) \\ pH = 5.17$

You might be interested in

.Cut up paper burns much more rapidly than an equivalent single piece of wood because of its...

tankabanditka [31]

Answer:

different reactants

Explanation:

because if you think about it what's really thick and it takes a lot longer to burn a piece of paper is super fit material which can just tear real easily just by ripping it with your fingers so if you think about it how fast it burns it's not how big the molecules are because paper has smaller molecules than wood would so the paper burns faster in differently so it's probably the reactant it's made of

3 0

3 years ago

Write a hypothesis: What is the mole ratio of the cation and the anion in a precipitate?

tankabanditka [31]

Answer:

The mole ratio of the cation and the anion in a precipitate is a simple fraction. ( im sorry if this dosent help a lot.)

Explanation:

8 0

3 years ago

The fuel used in many disposable lighters is liquid butane, C4H10

Charra [1.4K]

Answer:

1.45 *10^23 atoms C

Explanation:

3.50 g butane * 1 mol butane/58.1 g butane =0.06024 mol butane

in 1 mol C4H10 -------- 4 mol C

in 0.06024 mol C4H10 -------- 4*0.6024 = 0.241 mol C

0.241 mol C * 6.02*10^23 atoms C/1 mol C = 1.45 *10^23 atoms C

6 0

3 years ago

A balloon at 30.0°C has a volume of 222 mL. If the temperature is increased to 56.1°C and the pressure remains constant, what wi

svp [43]

Answer:

415.15 mL

Explanation:

To solve the statement, you can use the law of Charles - Gay Lussac, which states that "the volume of gas is directly proportional to its temperature at constant pressure." Mathematically:

$\frac{V1}{T1} = \frac{V2}{T2} = Constant$

You can calculate the volume V₂ Clearing it from the equation and replacing the values granted by the statement to perform the calculation:

V₂ = V₁ x T₂ / T₁ = 222 mL x 56.1 ° C / 30.0 ° C = 415.15 mL

Therefore, the gas at 56.1 ° C will occupy a volume of 415.15 mL

7 0

3 years ago

A pressure cooker contains 5.68 liters of air at a temperature of 394 K. If the absolute pressure of the air in the pressure coo

Arturiano [62]

Answer:

Explanation:

We shall find out volume of air at NTP or at 273 K and 10⁵ Pa ( 1 atm )

Let it be V₂

$\frac{P_1V_1}{T_1} =\frac{P_2V_2}{T_2}$

$\frac{2\times 10^5\times 5.68}{394} =\frac{10^5\times V_2}{273}$

V₂ = 7.87 litres

22.4 litres of any gas is equivalent to 1 mole

7.87 litres of air will be equivalent to

7.87 / 22.4 moles

= .35 moles .

7 0

3 years ago