When 100.0 mL of ethyl alcohol is heated from 10.0 C to 35.0 C, about how much thermal energy
1 answer:
Answer:
Q = 194.34 J
Explanation:
Given that,
100.0 mL of ethyl alcohol is heated from 10.0 C to 35.0 C.
We need to find the amount of thermal energy absorbed by the ethyl alcohol.
The density of ethyl alcohol is 0.790 g/mL.
The formula for heat absorbed is given by :
So, 194.34 J of thermal energy is absorbed by the ethyl alcohol.
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Answer:
The radius of the circle made by the person on the merry go round is 74.55 meters
Explanation:
The given parameters are;
The force the merry go round exerts on the rider = 1000 N
The time it takes the merry go round to make one complete revolution = 15 seconds
The weight of the person = 750 N
The radius of the circle made by the person on the merry go round = r
We have;
Where;
m = The mass of the person
v = The velocity of the person
= The centrifugal force acting on the person = 1,000 N
r = The radius of the circle made by the person on the merry go round
ω = Angular velocity = 2·π/15 rad/s
We have;
The mass of the person = The weight/(The acceleration due to gravity, g)
∴ The mass of the person = 750/9.81 ≈ 76.45 kg
By substituting the calculated and known values into the equation for the centripetal force, we have;
= m × ω² × r
1000 = 76.45 × (2·π/15)² × r
r = 1000/(76.45 × (2·π/15)²) = 74.55 m
The radius of the circle made by the person on the merry go round = r = 74.55 m.