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2 years ago

When 100.0 mL of ethyl alcohol is heated from 10.0 C to 35.0 C, about how much thermal energy

Physics

1 answer:

aliya0001 [1]2 years ago

5 0

Answer:

Q = 194.34 J

Explanation:

Given that,

100.0 mL of ethyl alcohol is heated from 10.0 C to 35.0 C.

We need to find the amount of thermal energy absorbed by the ethyl alcohol.

The density of ethyl alcohol is 0.790 g/mL.

The formula for heat absorbed is given by :

$Q=mc\Delta T\\\\As, d=\dfrac{m}{V}\\\\So,\\Q=dVc\Delta T\\\\Q=0.79\times 100\times 2.46\\\\Q=194.34\ J$

So, 194.34 J of thermal energy is absorbed by the ethyl alcohol.

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3 years ago

Read 2 more answers

(a) What is the minimum width of a single slit (in multiples of λ ) that will produce a first minimum for a wavelength λ ? (b) W

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Answer:

The minimum value of width for first minima is λ

The minimum value of width for 50 minima is 50λ

The minimum value of width for 1000 minima is 1000λ

Explanation:

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Wavelength = λ

For D to be small,

We need to calculate the minimum width

Using formula of minimum width

$D\sin\theta=n\lambda$

$D=\dfrac{n\lambda}{\sin\theta}$

Where, D = width of slit

$\lambda$ = wavelength

Put the value into the formula

$D=\dfrac{n\lambda}{\sin\theta}$

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$D=\dfrac{1\times\lambda}{1}$

$D=\lambda$

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$D=\dfrac{50\times\lambda}{1}$

$D=50\lambda$

(c). If the minimum number is 1000

Then, the width is

$D=\dfrac{1000\times\lambda}{1}$

$D=1000\lambda$

Hence, The minimum value of width for first minima is λ

The minimum value of width for 50 minima is 50λ

The minimum value of width for 1000 minima is 1000λ

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