A. P(492 < x-bar < 512)
<span>z = (492-502)/100/√90 </span>
<span>z = -0.95 is 0.1711 </span>
<span>z = (512-502)/100/√90 </span>
<span>z = 0.95 is 0.8289 </span>
<span>b. P(505 < x-bar < 525) </span>
<span>z = (505-515)/100/ √90 </span>
<span>z = -0.95 </span>
<span>z = (525-515)/100/ √90 </span>
<span>z = 0.95 </span>
<span>P(-0.95< z < 0.95) = 0.6578 </span>
<span>P(-0.95< z < 0.95) = 0.6578 </span>
<span>c. P(484 < x-bar < 504) </span>
<span>z = (484-494)/100/√100 </span>
<span>z = -1 is 0.1587 </span>
<span>z = (504-494)/100/√100 </span>
<span>z = 1 is 0.8413 </span>
<span>P(-1< z <1) = 0.6826</span>
26.8 or 26.8224 depends on what rounding they ask for
Answer:
30 inkjet printers
30 laser printers
Step-by-step explanation:
Let x be inkjet printer
Let y be the laser printer
Total printer produced per day = 60
This implies that x+y = 60
The company has 120 labor hours per day. If it has 1 labor hour to make a inkjet printer and 3 labor hours to make a laser printer, we will have
x + 3y = 120
So we have
x + y = 60 ........(1)
x + 3y = 120 ........(2)
Subtract equation 1 from 2
We have
2y = 60
y = 60/2
y = 30
Put y= 30 into equation 1
x + y = 60
x + 30 = 60
x = 60 -30
x = 30
Therefore we have 30 inkjet printers and 30 laser printer.
