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Westkost [7]
2 years ago
5

23. About how much would 4 horses weigh? Write the weight two different ways.​

Mathematics
2 answers:
ycow [4]2 years ago
8 0

An average horse weighs 900-2,000 pounds, depending on size and breed. A lean, racing fit Thoroughbred, for example, has an average weight of 900-1,100 pounds, while the average Clydesdale (think Budweiser) weighs in at 1,800-2,000 pounds

Leona [35]2 years ago
7 0

Answer:

If one horse will weigh about 2000 pounds, or 1000kg, then four horses will weigh about 8000 pounds or 4000kg

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Helga [31]

Answer:

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Step-by-step explanation:

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6 0
2 years ago
WILL GIVE ALOT OF POINTS HELP FAST One cold night the temperature was 0 degrees at 8 p.m. The temperature dropped at a constant
den301095 [7]

Answer:

4.4

Step-by-step explanation:

16.8 was for 4 hour

divide 4 by 16.8

you get 4.2 per hour

so you need 1 hour

1 hour would be 4.2

temp would be -4.2 at 9pm

4 0
3 years ago
Read 2 more answers
Which of these sets of ordered pairs below does not represent a function?
Step2247 [10]

Answer:

0,0

Step-by-step explanation:

The function set is empty

7 0
3 years ago
The graph below shows two polynomial functions, f(x) and g(x): Graph of f of x equals x squared minus 2 x plus 1. Graph of g of
IceJOKER [234]

9514 1404 393

Answer:

  (c)  f(x) is an even degree polynomial with a positive leading coefficient.

Step-by-step explanation:

The leading terms of the two functions are ...

  f(x): x² (even degree, positive coefficient: 1)

  g(x): x³ (odd degree, positive coefficient: 1)

Then it is true that ...

  f(x) is an even degree polynomial with a positive leading coefficient

8 0
2 years ago
Simplify the rational expression.  State any restrictions on the variable.
AveGali [126]

Answer:

The last choice.

Step-by-step explanation:

\dfrac{k^2-k-2}{k^2-4k-5}=\dfrac{(k+1)(k-2)}{(k+1)(k-5)}=\dfrac{k-2}{k-5}

The value of k must be restricted from being one that makes the original denominator zero. Hence k ≠ -1 or 5.

7 0
2 years ago
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