All categories

3 years ago

If g(x) = 725, which of the following is true?

Mathematics

1 answer:

kotykmax [81]3 years ago

4 0

Answer:

B and D

Step-by-step explanation:

The g(x) = 725 makes no sense to me....

however g(x) = -2x/(x-3) can be solved by plugging x = value into function

a) g(x) = -2x/(x-3)

g(0) = -2(0)/(0-3) = -3

= 0/-3 = 0 ≠ -3 FALSE

b) g(x) = -2x/(x-3) = 1

g(1) = -2(1)/(1-3) = 1

= -2 / -2 = 1 equals 1 TRUE

c) g(x) = -2x/(x-3)

g(2) = -2(2)/(2-3) < g(4) = -2(4)/(4-3)

= -4 / -1 < -8 / 1

= 4 is greater than - 8 FALSE

d) g(x) = -2x/(x-3) both values were already calcuated

g(1) = -2(1)/(1-3) = 1 < g(2) = -2(2)/(2-3) = 4

1 < 4 TRUE

You might be interested in

The cost of controlling emissions at a firm rises rapidly as the amount of emissions reduced increases. Here is a possible model

Nadusha1986 [10]

Answer:

$\bar C = 4100\,dollars$

Step-by-step explanation:

a) The average value of a function is given by the following integral:

$\bar C = \frac{\int\limits^{q_{max}}_{0} {4100+90\cdot q^{2}} \, dq }{q_{max}}$

$\bar C = \frac{1}{q_{max}}\cdot \left(4100\cdot q_{max} + 30\cdot q_{max}^{3} \right)$

$\bar C = 4100 + 30\cdot q_{max}^{2}$

b) The determination of the minimum average daily cost per pound of pollutant is done by the First Derivative Test and the Second Derivative Test, which is:

$\bar C' = 60\cdot q_{max}$

$60\cdot q_{max} = 0$

$q_{max} = 0$

$\bar C'' = 60$ (absolute minimum).

The level of reduction corresponding to the lowest average daily cost per pound of pollutant is:

$\bar C = 4100\,dollars$

3 0

4 years ago

A gardener has 140 feet of fencing to put around a rectangular vegetable garden. The function A(w)= 70w - w^2 gives the garden's

Alexus [3.1K]

The largest area that can be enclosed will be that of a square (140 ft)/4 = 35 ft on a side. Such a square has an area of (35 ft)² = 1225 ft², not enough for the garden to be 1300 ft². This tells us the solution to the equation you're being asked to write is non-real.

_____

Putting the given numbers in the area equation, you have

... 1300 = 70w -w²

Multiplying by -1 and completing the square, we have

... w² -70w +35² = -1300 +35²

... (w -35)² = 1225 -1300 = -75

Taking the square root shows us the solution is non-real.

... w - 35 = ±√(-75) = ±5i√3

... w = 35 ± 5i√3 . . . . . . . . . after adding 35. These are complex solutions.

5 0

4 years ago

What is 25kg in a ratio of 2:3:5