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3 years ago

ILL MARK BRAINLIEST IF GOTTEN RIGHT IF YOU DONT KNOW DONT ANSWER

Mathematics

1 answer:

lukranit [14]3 years ago

6 0

Answer:

A) CPCTC

Step-by-step explanation:

This part of the proof occurs right after two triangles are proven congruent. One could now conclude and establish that every part of each congruent triangle is congruent, which is what is most likely happening in this scenario.

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A(n) _____ is not an example of an agreement Lease Month to month Annual Fine print

oee [108]

An ANNUAL is not an example of an agreement.
A lease agreement is usually documented when a tenant rent an apartment from a landlord. A lease can be for a period of months or year. A yearly lease,which is not renewed automatically is termed month to month. Fine print refers to contract terms and conditions that are not included in the main body of an agreement but they are instead placed in footnotes or in another document. Thus, lease, month to month and fine print are all examples of agreement.
An annual refers to the financial information of a company which is printed on a yearly basis, thus, an annual is not an example of agreement.

5 0

3 years ago

Read 2 more answers

A taxi company charges $1.00 for the first mile (or part of a mile) and 20 cents for each succeeding tenth of a mile (or part).

meriva

Step-by-step explanation:

solving functions separately.

1st: from given data taxi charges $1.00 for the first mile.so it is first rule of function.

$y_{1} =1 , 0$

2nd: the company charge $0.20 per tenth of a mile.so 2nd rule of the function will be

$y_{2} =1+0.2.10(x-1)$

simplifying

$y_{2} =1+2(x-1)$

$y_{2} =x+2x-2$

$y_{2} =x$ , $1$

piece wise function is f(x)={2 , 0<x<1

{x , 1<x<2

the graph of the function is given below

7 0

3 years ago

Solve for: <img src="https://tex.z-dn.net/?f=x%5E%7B2%7D%20%20%2B%205x%20%3D%201" id="TexFormula1" title="x^{2} + 5x = 1

mixer [17]

$x^2+5x-1=0\\x^2+5x+(\frac{5}{2})^2-(\frac{5}{2})^2-1=0\\(x+\frac{5}{2})^2-\frac{25}{4}-\frac{4}{4}=0\\(x+\frac{5}{2})^2-\frac{29}{4}=0\\(x+\frac{5}{2})^2=\frac{29}{4}\\x+\frac{5}{2}=\sqrt{\frac{29}{4}} , x+\frac{5}{2}=-\sqrt{\frac{29}{4}}\\x=\frac{\sqrt{29} }{2} - \frac{5}{2} , x=-\frac{\sqrt{29} }{2} - \frac{5}{2} \\x=\frac{\sqrt{29}-5 }{2} , x=-\frac{\sqrt{29} -5}{2}$

4 0

4 years ago

A sequence of Bernoulli trials consists of choosing components at random from a batch of components. A selected component is eit

Drupady [299]

Answer:

a) 0.0287 = 2.87% probability that three non-defective components in a batch of seven components.

b) 0.0336 = 3.36% probability that 8 non-defective components are drawn before the first defective component is chosen.

Step-by-step explanation:

A sequence of Bernoulli trials composes the binomial distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

The probability that a selected component is non-defective is 0.8

This means that $p = 0.8$

a) Three non-defective components in a batch of seven components.

This is P(X = 3) when n = 7. So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 3) = C_{7,3}.(0.8)^{3}.(0.2)^{4} = 0.0287$

0.0287 = 2.87% probability that three non-defective components in a batch of seven components.

b) 8 non-defective components are drawn before the first defective component is chosen.

Now the order is important, so the we just multiply the probabilities.

8 non-defective, each with probability 0.8, and then a defective, with probability 0.2. So

$p = (0.8)^8*0.2 = 0.0336$

0.0336 = 3.36% probability that 8 non-defective components are drawn before the first defective component is chosen.

4 0

3 years ago

6. Look at this graph: Is this relation a function? Yes or no

zmey [24]

Both are not functions because functions cannot have repeating x values

3 0

3 years ago

Read 2 more answers