T = 5, so after 5 years
p(t) = t^3 - 14t^2 + 20t + 120
Take derivative to find minimum:
p’(t) = 3t^2 - 28t + 10
Factor to solve for t:
p’(t) = (3t - 2)(t - 5)
0 = (3t - 2)(t - 5)
0 = 3t - 2
2 = 3t
2/3 = t
Plug 2/3 into original equation, this is a maximum. We want the minimum:
0 = t - 5
5 = t
Plug back into original:
5^3 - 14(5)^2 + 20(5) + 120
125 - 14(25) + 100 + 120
125 - 350 + 220
- 225 + 220
p(5) = -5
Answer:
The player that placed the knight after the first person at the start of the game. There in his turn whatever role the knight played he both had opportunity to space each knight strategically and use the knight to protect whatever wins the game.
Step-by-step explanation:
Maths is 81/80 =1
This is a square, and so all the sides will be the same measurements. Note that you are given an area, so you'll have to root the total area to get a side.
√400 = 20
One side's measurements is 20 in
hope this helps
Step-by-step explanation:
it will take you 15 minutes
Answer:
28
Step-by-step explanation:
VZ = ZY
2x +2 = 3x -4
6 = x . . . . . . . . add 4-2x to both sides
VZ = 2x +2 = 2(6) +2 = 14
Now we can find VY.
VY = VZ + ZY = 14 + 14 . . . . . . VY is the total of the two halves
VY = 28
