1) pathogen enters body and releases chemoattractants
2) a phagocyte/macrophage is attracted by these chemicals
3) the phagocyte engulfs the pathogen using its pseudopodia
4) the membranes of both organisms fuse forming a phagosome
5) lysosomers in the phogocyte fuse with the phagosome, forming a phagolysosome
6) these enzymes digest the pahogen (hydrolyse the bonds)
7) the antigens of the pathogen are placed on the surface of the phagocyte making an APC (antigen presenting cell)
Is this a serious question ? loool
Answer:
E. 0.0.
Explanation:
The measure of crossing over coincidence interrelatedness between one cross over and another in a given pair of chromosome is known as what is called Interference.
Given that :
the interference value = 1
The probability of recombination between genes A and B is zero i.e 0.0 because:
when another gene co-occur with a particular gene during cross over, the coefficient of coincidence decreases. We know that the interference is maximum at 1, we can say it ranges from 0-1; now that two recombination is taking place in two genes,the probability is likely to decrease from 1 to 0.0
Similarly; Since the probability of recombination is taking place between two genes i.e genes A and B. Then there is no probability of double crossover when interference value = 1 but when it is zero there is probability of double crossover to occur. With that being said, the probability of recombination between genes A and B is 0.0
The answer is biodiversity.
Answer:
a. In image attached.
b. 25% or a 1 in 4 chance.
c. 75% or a 3 in 4 chance.
Explanation:
B = Dominant (brown gene)
r = Recessive (red gene)
If two parents both have Br genes, they will both have brown hair.
The Punnet square will look like the image attached.
